1. The number of Caesar Ciphers on an alphabet of 53 symbols is NOTE * the answe
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Question
1. The number of Caesar Ciphers on an alphabet of 53 symbols isNOTE * the answer is not 25
2. If an attacker wants to decrypt a secret message encrypted using a Caesar cipher with an alphabet of 68 symbols, How many ciphers does he/she has to try in order to find the original message?
Note : the answer is not 25
USING THE DIVISION ALGORITHM
3. The quotient of -37 divided by 6 is
4. The remainder of -37 divided by 6 is
5. The quotient of 54 divided by -8 is
6. The remainder of 54 divided by -8 is
7. The quotient of -65 divided by -10 is
8. The remainder of -65 divided by -10
1. The number of Caesar Ciphers on an alphabet of 53 symbols is
NOTE * the answer is not 25
2. If an attacker wants to decrypt a secret message encrypted using a Caesar cipher with an alphabet of 68 symbols, How many ciphers does he/she has to try in order to find the original message?
Note : the answer is not 25
USING THE DIVISION ALGORITHM
3. The quotient of -37 divided by 6 is
4. The remainder of -37 divided by 6 is
5. The quotient of 54 divided by -8 is
6. The remainder of 54 divided by -8 is
7. The quotient of -65 divided by -10 is
8. The remainder of -65 divided by -10
1. The number of Caesar Ciphers on an alphabet of 53 symbols is
NOTE * the answer is not 25
2. If an attacker wants to decrypt a secret message encrypted using a Caesar cipher with an alphabet of 68 symbols, How many ciphers does he/she has to try in order to find the original message?
Note : the answer is not 25
USING THE DIVISION ALGORITHM
3. The quotient of -37 divided by 6 is
4. The remainder of -37 divided by 6 is
5. The quotient of 54 divided by -8 is
6. The remainder of 54 divided by -8 is
7. The quotient of -65 divided by -10 is
8. The remainder of -65 divided by -10
Explanation / Answer
1. 53 caeser ciphers we can have. We have 53 choices of keys that is shifting characters by one place to 53 places.
2. Hacker has to try 68 ciphers. As we have 68 choices for keys, Hacker need to try all 68 keys.
Using division algorithm
-37 = Q*6 + R where Q = Quotient and R= Reminder
-37 = -7*6 + 5
3. Quotient of -37 / 6 = -7
4. Reminder of -37 / 6 = 5
54 = -6*-8 + 6
5. Quotient of 54/-8 = -6
6. Reminder of 54/-8 = 6
-65 = 7*-10 + 5
7. Quotient of -65/-10 = 7
8.Reminder of -65/-10 = 5
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