package week_2; import static input.InputUtils. stringInput ; /** Finish this pr

Question

 package week_2;  import static input.InputUtils.stringInput;  /**    Finish this program to test if a String contains all of the   punctuation characters from the number keys on a standard US keyboard:    !@#$%^&*()    So, the String "abc!@#$%^&*()def" contains all the characters.  The String ")(*&^%$#@!" contains all the characters.  The String "a)(b*&c^%d$#e@!" contains all the characters.    The String "abc$*^def" does not.    Your code should NOT use 10 if statements!    In your program, finish the method that tests if a String contains all the  characters in another String. Make sure this method would work with any two input Strings.    */ public class Question_8_String_Contains_Chars {      static final String PUNCTUATION = "!@#$%^&*()";      public static void main(String[] args) {              // You don't need to modify the main method.                  String testString = stringInput("Enter the string to test: ");          boolean containsChars = containsChars(PUNCTUATION, testString);          System.out.printf("Does the string %s contain all the characters %s? %b", testString, PUNCTUATION, containsChars);      }      public static boolean containsChars(String characters, String testString) {          // TODO check if the String testString contains all the characters in the String characters         // Example: if characters = "!@#$%^&*()" and testString = "!Q@W#E$R%T^Y&U*I(O)P" return true         // Example: if characters = "!@#$%^&*()" and testString = "** Hello! (Java)" return false         // Example: if characters = "QWERTY" and testString = "The first row of keys on a US keyboard is 'QWERTYUIOP'" return true         // Example: if characters = "QWERTY" and testString = "qwerty" return false              // Make sure your method works with any Strings in the characters and testString variable.                           return false;     } 

Explanation / Answer

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