Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

rovide best-case and worst-case running time and space complexity analysis in Bi

ID: 3746708 • Letter: R

Question

rovide best-case and worst-case running time and space complexity analysis in Big-Oh notation for the following pow_2 method. For each case, provide an example input pair and brief explanation. Big-O Notation Example Input Explanation Best-Case Running Time Worst-Case Running Time Best-Case Space Complexity Worst-Case Space Complexit public static long pow_2(long x, int n) { if (n-8) if (n1) if(n % 2-0) { return 1; return x; return pow 2X, n / 2) pow2x, n/ 2 ); return pow 2(x * x, n / 2) * x; else

Explanation / Answer

Big-O Notation

Example Input

Explanation

Best-Case Running Time

O(1) i.e. Constant

X = any number ; n=1

Since n==1 it will return from the function returning the value X

Worst-Case Running Time

O(n) i.e. Linear

X = any number ; n=a number which is a power of 2

Here the function will keep calling itself until n becomes equal to 1 which will lead to

(2*n-1) iterations

Best-Case Space Complexity

O(1) i.e. Constant

X = any number ; n=1

It will just return X without using any extra space i.e. will only use constant space

Worst-Case Space Complexity

O(n) i.e. Linear

X = any number ; n=a number which is a power of 2

This will use stack for recursive calls and 2*n-1 space will be occupied

Big-O Notation

Example Input

Explanation

Best-Case Running Time

O(1) i.e. Constant

X = any number ; n=1

Since n==1 it will return from the function returning the value X

Worst-Case Running Time

O(n) i.e. Linear

X = any number ; n=a number which is a power of 2

Here the function will keep calling itself until n becomes equal to 1 which will lead to

(2*n-1) iterations

Best-Case Space Complexity

O(1) i.e. Constant

X = any number ; n=1

It will just return X without using any extra space i.e. will only use constant space

Worst-Case Space Complexity

O(n) i.e. Linear

X = any number ; n=a number which is a power of 2

This will use stack for recursive calls and 2*n-1 space will be occupied