Python I have this code import subprocess import datetime from time import sleep

Question

Python

I have this code

import subprocess
import datetime
from time import sleep

i = 0
while i<100:
try:
subprocess.check_output(['ping -l 1000 www.google.com c- 100'])
except:
print("Ping google.com:", datetime.datetime.now())

def pumpcheck(timer_in_minutes):
time_clicked = datetime.datetime.now()
now = time_clicked
timeDiff = datetime.timedelta(minutes=int(timer_in_minutes=.001))

while(time_clicked + timeDiff > now):
print ('pumpOn')
now = datetime.datetime.now()
sleep(2)
print ('pumpOff')

i += 1

I need to loop 120 times and stop Can you help?

Please type your answer

Explanation / Answer

I got your question, please provide indentation next time onwards, you want the second loop (while loop, in the pumpcheck) to be executed for only 120 times. You can use a counter, that will be implemented at every iteration, and breaks the loop at 120th iteration.

I have modified your code accordingly, I initialized a counter as variable j , which would loop after each loop, and breaks the loop if it is equal or greater than 120. This will let the loop runs exactly 120 times.

I bother if you want to use i as counter and want to break at, when i == 120, just replace it with the if condition and remove the j initialization.

Here is the code:

import subprocess
import datetime
from time import sleep

i = 0
while i<100:

try:

subprocess.check_output(['ping -l 1000 www.google.com c- 100'])

except:

print("Ping google.com:", datetime.datetime.now())

def pumpcheck(timer_in_minutes):

time_clicked = datetime.datetime.now()

now = time_clicked

timeDiff = datetime.timedelta(minutes=int(timer_in_minutes=.001))

while(time_clicked + timeDiff > now):

j=0

print('pumpOn')

if j >= 120:

break

now = datetime.datetime.now()

sleep(2)

print ('pumpOff')

i += 1

j += 1

Here, above is the code.

Hope this will help you. If you have any further query, feel free to ask.

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