D Question 1 4 pts n a byte-addressable memory. The byte address of memory word
ID: 3750001 • Letter: D
Question
D Question 1 4 pts n a byte-addressable memory. The byte address of memory word 1510 is 0x If the number OxFF223344 is stored at word 1510 in a big-endian machine then the byte addressed by Ox3D has the data value Ox D | Question 2 12 pts Convert the three instructions below into their hexadecimal sequence fie. hexadecimal version of their binary sequence representations in memory) 1. add $t0, $s0, $s1 in hexadecimal is Ox 2·lw St0, 0x20(St7) in hexadecimal is Ox 3. addi $50, SO,-10 in hexadecimal is Ox Question 3 4 pts Suppose that $s3 initially contains 0x23456789. The instruction sw 5s3. 4150) stores the data in register $33 into memory word number . This word has the byte address Ox After this sw instruction has stored in memory, the instruction Ib $s3, 450) londs dats into $:3. In a big endian machine the value imide $-3 wil be o and in a itterentian machine the value will be0Explanation / Answer
ANSWER:
b)
Convert the three instructions below into their hexadecimal sequence (i.e. hexadecimal version of their binary sequence representations in memory)
1. add $t0, $s0, $s1 in hexadecimal is 0x02114020
Explanation:-
R-type instruction format:-
Opcode(6-bit) Rs(5-bit) Rt(5-bit) Rd(5-bit) shamt(5-bit) func(6bit)
000000 $s0(10000) $s1(10001) $t0(01000) 00000 100000
Convert into hex->0X02114020
2. lw $t0, 0x20($t7) in hexadecimal is 0x8de80020
Explanation:-
I-type instruction format:-
Opcode(6-bit) Rs(5-bit) Rt(5-bit) address(16-bit)
100011 $t7(01111) $t0(01000) 0000000000100000
Convert into hex->0X8de80020
3. addi $s0, $0, 10 in hexadecimal is 0x2010fff6
Explanation:-
I-type instruction format:-
Opcode(6-bit) Rs(5-bit) Rt(5-bit) Immediate(-ve 2's complement10)
001000 $0(00000) $s0(10000) 1111111111110101
Convert into hex->0X2010fff6
(C)
Explanation:-
I-type instruction format:-
Opcode(6-bit) Rs(5-bit) Rt(5-bit) address(16-bit)
101011 $t0(00000) $s3(10011) 000000000000000100
Convert into hex->0Xac130004
---------------------------------------------------------------
I-type instruction format:-
Opcode(6-bit) Rs(5-bit) Rt(5-bit) address(16-bit)
100100 $t0(00000) $s3(10011) 000000000000000100
Convert into hex->0X80130004
as per chegg rules i have answer two parts out of three
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