You are one of four carpenters assigned to complete a short construction project

Question

You are one of four carpenters assigned to complete a short construction project. Right before the start of the project, one of your fellow carpenters was hospitalized and will not be available to work on the project. Develop a resource-constrained schedule to see how long the project will take with only 3 carpenters. Be sure to record the order in which you schedule the activities using the scheduling heuristics. Activities 1, 2, 3, 4, 5, 7, and 8 require 2 carpenters to complete. Activity 6 requires only 1 carpenter. No splitting of activities is possible. You will receive a bonus if the project is completed within 13 days.

6 5 8 2 0 6 28 7 10 0 2 0 8 2 10 0 2 0 0 2 0 0 2 2 0 2 0 10 8 12 0 2 0 10 2 12 0 2 0 0 1 0 7 310 Legend ES ID EF SLK RES SLK LS DUR LF Schedule resource load chart with ES and slack updates D Resource IDuration IES ILF ISL TP1 TP 2 TP 3 TP &TP; STP6 TPT TP TP TP 10 TP 11 TP 12 TP 13 TP 14 TP 15 0 2 0 2 2 5 6 6 10 1 10 12 0 Resources scheduled Resources available Note: Recall, in the schedule resource load chart the time-constrained scheduling interval (ES through LF) has been shaded. Any resource scheduled beyond the shaded area will delay the project. "TP" stands for time period List the order in which you scheduled the activities of the project First Second Third Fourth Fifth Sixth Seventh Eighth

Explanation / Answer

Resources Duration Predecessor 1 2 3 4 5 6 7 8 9 10 11 12 13 ES EF LS LF Slack = LS-ES Critical if Slack = 0 1 2 2 --- 1 1 1 2 1 2 0 Yes 2 2 2 1 2 2 3 4 4 5 1 No 3 2 3 1 3 3 3 3 5 3 5 0 Yes 4 2 1 2,3 4 6 6 6 6 0 Yes 5 2 2 4 5 5 7 8 7 8 0 Yes 6 1 3 4 6 6 6 7 9 8 10 1 No 7 2 2 5 7 7 9 10 9 10 0 Yes 8 2 2 6,7 8 8 11 12 11 12 0 Yes The schedule in which the activities are scheduled are : First 1 Second 3 We have scheduled 3 earlier than 2 as in 2 there is a slack of 1 time period Third 2 Fourth 4 Fifth 5 Sixth 6 Seventh 7 Eighth 8 Our revised schedule will be as follows : Resources Duration Predecessor 1 2 3 4 5 6 7 8 9 10 11 12 13 ES EF LS LF Slack = LS-ES Critical if Slack = 0 1 2 2 --- 1 1 1 2 1 2 0 Yes 3 2 3 1 3 3 3 3 5 3 5 0 Yes 2 2 2 1 2 2 3 4 4 5 1 No 4 2 1 2,3 4 6 6 6 6 0 Yes 5 2 2 4 5 5 7 8 7 8 0 Yes 6 1 3 4 6 6 6 7 9 8 10 1 No 7 2 2 5 7 7 9 10 9 10 0 Yes 8 2 2 6,7 8 8 11 12 11 12 0 Yes Here activities critical are 1, 3 , 4,5 , 7 & 8. Slack for activity 1 is 0 , for activity 2 it is 1 and for activity 6 it is 1.

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