Perform required calculations related to initial IPv4 network ID 192.168.89.35/2

Question

Perform required calculations related to initial IPv4 network ID 192.168.89.35/24 to support subnet design and answer questions 43, 44, and 45. Design the modified mask for 5 subnets (the only requirement – no workstation constraint), identify the subnet IDs and then identify the range of host addresses for the first subnet. Remember that you borrow the left-most bits from the byte of interest to add to the network ID. Also remember that: number of subnets = (2^bits) -2 and 2^1 = 2        2^2 = 4      2^3 = 8      2^4 = 16           2^5 = 32          

Q1. How many bits must be borrowed from the host part of the address to gain 5 subnets and what is the decimal version of the modified subnet mask? (Select only one)

a. 1 bit moved and the modified subnet mask is 255.255.255.16

b. 1 bit moved and the modified subnet mask is 255.255.255.128

c. 3 bits moved and the modified subnet mask is 255.255.255.192

d. 3 bits moved and the modified subnet mask is 255.255.255.224

Q2. The magic number is 32 so select the one item below that contains the correct first four subnet IDs.

a. 192.168.89.35, 192.168.89.99, 192.168.89.163, 192.168.89.227

b. 192.168.89.0, 192.168.89.32, 192.168.89.64, 192.168.89.96

c. 192.168.89.0, 192.168.89.62, 192.168.89.124, 192.168.89.190

d. 192.168.89.32, 192.168.89.64, 192.168.89.96, 192.168.89.128

Q3. The range of addresses for the first subnet is ___ (Select only one)

a. 192.168.89.1 to 192.168.89.31

b. 192.168.89.1 to 192.168.89.32

c. 192.168.89.0 to 192.168.89.31

d. 192.168.89.0 to 192.168.89.32

Explanation / Answer

1) Answer: 255.255.255.224

192.168.89.35/24

We can see that SUBNET_MASK is 255.255.255.0

=> 3 bits means three ones from hosts
=> 11100000 = 128 + 64 + 32 = 224

Means 255.255.255.224

2)b. 192.168.89.0, 192.168.89.32, 192.168.89.64, 192.168.89.96

3) c. 192.168.89.0 to 192.168.89.31

192.168.89. 00100011 & 11111111.11111111.11111111.00000000
=> 192.168.89. 0 is the start address
=> 192. 168.89.31 end address

Thanks, PLEASE UPVOTE if helpful

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