This questions uses SQL Below are the tables that will be used. CREATE TABLE `St

Question

This questions uses SQL

Below are the tables that will be used.

CREATE TABLE `Student`(
`s_id` VARCHAR(20),
`s_name` VARCHAR(20) NOT NULL DEFAULT '',
`s_birth` VARCHAR(20) NOT NULL DEFAULT '',
`s_sex` VARCHAR(10) NOT NULL DEFAULT '',
PRIMARY KEY(`s_id`)
);

insert into Student values('01' , ' Cobb' , '1990-01-01' , ' Male');
insert into Student values('02' , ' Arthur', '1990-12-21' , ' Male');
insert into Student values('03' , 'Ariadne' , '1990-05-20' , 'Female');
insert into Student values('04' , 'Eames' , '1990-08-06' , 'Male');
insert into Student values('05' , 'Mal' , '1991-12-01' , 'Female');
insert into Student values('06' , 'Blonde' , '1992-03-01' , 'Female');
insert into Student values('07' , 'Saito' , '1989-07-01' , 'Male');
insert into Student values('08' , 'Miranda' , '1990-01-20' , 'Female');

CREATE TABLE `Course`(
`c_id` VARCHAR(20),
`c_name` VARCHAR(20) NOT NULL DEFAULT '',
`t_id` VARCHAR(20) NOT NULL,
PRIMARY KEY(`c_id`)
);
insert into Course values('01' , 'Math' , '02');
insert into Course values('02', 'French', '01');
insert into Course values('03' , 'Art', '03');

CREATE TABLE `Teacher`(
`t_id` VARCHAR(20),
`t_name` VARCHAR(20) NOT NULL DEFAULT '',
PRIMARY KEY(`t_id`)
);
insert into Teacher values('01', 'Frank');
insert into Teacher values('02', 'Einstein');
insert into Teacher values('03', 'Newton');  

CREATE TABLE `Score`(
`s_id` VARCHAR(20),
`c_id` VARCHAR(20),
`s_score` INT(3),
PRIMARY KEY(`s_id`,`c_id`)
);
insert into Score values('01' , '01' , 80);
insert into Score values('01' , '02' , 90);
insert into Score values('01' , '03' , 99);
insert into Score values('02' , '01' , 70);
insert into Score values('02' , '02' , 60);
insert into Score values('02' , '03' , 80);
insert into Score values('03' , '01' , 80);
insert into Score values('03' , '02' , 80);
insert into Score values('03' , '03' , 80);
insert into Score values('04' , '01' , 50);
insert into Score values('04' , '02' , 30);
insert into Score values('04' , '03' , 20);
insert into Score values('05' , '01' , 76);
insert into Score values('05' , '02' , 87);
insert into Score values('06' , '01' , 31);
insert into Score values('06' , '03' , 34);
insert into Score values('07' , '02' , 89);
insert into Score values('07' , '03' , 98);

What command query will show the below table result.

Find the students who fail exam(s), show their name and the number of courses they failed. (fail: score 60). Hint: Use GROUP BY to group students. Your result table should look like this: StuName NumFailed Eames Blonde 2

Explanation / Answer

Two queries(ways) can produce the same result.

Query-1: Way-1

SELECT S.s_name StuName,count(C.c_id) NumFailed FROM student S JOIN score SR
ON S.s_id=SR.s_id JOIN course C
ON SR.c_id=C.c_id
WHERE SR.s_score<60
GROUP BY StuName
ORDER BY NumFailed DESC;

Query-2: Way 2

SELECT S.s_name StuName,count(S.s_id) NumFailed FROM student S JOIN score SR
ON S.s_id=SR.s_id
WHERE SR.s_score<60
GROUP BY StuName
ORDER BY NumFailed DESC;

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