Why is the 4mb = 2^22 instead of 4*2^20 what am I missing here and the same for

Question

Why is the 4mb = 2^22 instead of 4*2^20 what am I missing here and the same for 32mb = 2^25 how do we determine the power ?

2- Suppose a processor of the Harvard architecture has 4MB instruction memory and 32MB data memory. If the memory address bus is shared between instruction memory and data memory, design a memory allocation scheme for this processor (i.e. address range for the instruction memory and the data memory). Solution: 4MB 22 bytes, Address range Ox0000_0000 -0x003F_FFFF 32MB = 225 bytes, Address range 0x0000 0000-0x01FFFFFF There are many ways to divide the space. For example: Instruction memory: 0x0010 0000-ox013F FFFF Data Memory: 0x2000_0000 0x21FF_FFFF

Explanation / Answer

4MB = 2^22B instead of 4*2^20B actullay both are equals since 4=2^2 , 4*2^20B=>2^2*2^20B => 2^(2+20) => 2^22B

this is same for 32MB = 2^25B , 32=2^5 , so 32mb =2^5MB => 2^5*2^20B => 2^(5+20)B => 2^25B,

b indicates bit,

B indicates Byte remember this also.

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