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//This program is going to show the sum, average and print outputs in order. #in

ID: 3759416 • Letter: #

Question

//This program is going to show the sum, average and print outputs in order.
#include <iostream>
#include <string>
using namespace std;

int main()
{
   int i;
   int Array[10];

   for (i = 0; i < 10, i++)
   {
       cin >> Array[i];
   }

   highest = Array[0];
   lowest = Array[0];

   for (i = 1; i < 10; i++)
   {
       if (Array[i] > highest) highest = Array[i];
       if (Array[i] < lowest) lowest = Array[i];
   }

   system("pause");
   return 0;
}

Modify this program to meet these requirements:

Write a program that lets the user enter 10 values into an array. The program should then display the largest, the smallest, the sum, and the average values.

Output should print:

The values are as following:

The smallest value is:

The highest value is:

The sum is:

The average is:

The values printed should be sorted from least to greatest.

Explanation / Answer

#include <iostream>
#include <string>
using namespace std;

int main()
{
   int i,sum=0,avg;
   int Array[10];

//Input 10 elements

for (i = 0; i < 10, i++)
   {
       cin >> Array[i];

//sum calculation

sum=sum+array[i];
   }

//Finding the highest and lowest value

//initially set the first elemnt of array itself as highest and lowest

highest = Array[0];
   lowest = Array[0];

   for (i = 1; i < 10; i++)
   {

//calculating lowest and highest
       if (Array[i] > highest)highest = Array[i];
       if (Array[i] < lowest) lowest = Array[i];
   }

//Formula calculating average of 10 elements

avg=sum /10;

//Printing the values of array

cout<<"The values are as following:";

for(i=0;i<10;i++)

{

cout<<array[i];

}

//Print small value in array

cout<<"The smallest value is"<<lowest<<endl;

//Print large value in array

cout<<"The highest value is"<<highest<<endl;

//Print sum of all values in array

cout<<"The sum is"<<sum<<endl;

//Print average of all values in array

cout<<"The avg is"<<avg<<endl;

system("pause");
   return 0;
}