Create a modified version of the program below so that the spaces, punctuation a

Question

Create a modified version of the program below so that the spaces, punctuation and changes in uppercase and lowercase are not considered when determining wheter a string is a palindrome.

//********************************************************************
// PalindromeTester.java Author: Lewis/Loftus
//
// Demonstrates the use of nested while loops.
//********************************************************************

import java.util.Scanner;

public class PalindromeTester
{
   //-----------------------------------------------------------------
   // Tests strings to see if they are palindromes.
   //-----------------------------------------------------------------
   public static void main(String[] args)
   {
String str, another = "y";
int left, right;

Scanner scan = new Scanner(System.in);

while (another.equalsIgnoreCase("y")) // allows y or Y
{
   System.out.println("Enter a potential palindrome:");
   str = scan.nextLine();

   left = 0;
   right = str.length() - 1;
while (str.charAt(left) == str.charAt(right) && left < right)
   {
left++;
right--;
   }

   System.out.println();

   if (left < right)
System.out.println("That string is NOT a palindrome.");
   else
System.out.println("That string IS a palindrome.");

   System.out.println();
   System.out.print("Test another palindrome (y/n)? ");
   another = scan.nextLine();
}
   }
}

Explanation / Answer

Hey. You din't offered any testcases. Anyways, I solved thr problem for you, upto my understanding. If you need any further details, just revert.

Here, given a raw string, I'm just trying to move on, when a non numeric and non alphabetic character encounters, without any comparison.

The logic is here with:

//********************************************************************
// PalindromeTester.java Author: Lewis/Loftus
//
// Demonstrates the use of nested while loops.
//********************************************************************

import java.util.Scanner;

public class PalindromeTester
{
//-----------------------------------------------------------------
// Tests strings to see if they are palindromes.
//-----------------------------------------------------------------
public static void main(String[] args)
{
String str, another = "y";
int left, right;

Scanner scan = new Scanner(System.in);

while (another.equalsIgnoreCase("y")) // allows y or Y
{
System.out.println("Enter a potential palindrome:");
str = scan.nextLine();

left = 0;
right = str.length() - 1;
String string;

while ( left < right)
{
//If the left character is neither alphabet nor digit, proceed.
if(!Character.isLetter(str.charAt(left)) && !Character.isDigit(str.charAt(left)))
{
left++;
continue;
}
//If the right character is neither alphabet nor digit, proceed.
if(!Character.isLetter(str.charAt(right)) && !Character.isDigit(str.charAt(right)))
{
System.out.println("0");
right--;
continue;
}
//If it is either digit or alphabet, then compare.
//If equal proceed.
if(str.charAt(left) == str.charAt(right))
{
left++;
right--;
continue;
}
//If not, conclude its not a palindrome.
break;
}

System.out.println();

if (left < right)
System.out.println("That string is NOT a palindrome.");
else
System.out.println("That string IS a palindrome.");

System.out.println();
System.out.print("Test another palindrome (y/n)? ");
another = scan.nextLine();
}
}
}

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