Write a function that takes as parameter a character array, which may contains l

Question

Write a function that takes as parameter a character array, which may contains lowercase, uppercase, digits, and other special symbols (e.g, *, $, ...), and outputs the number of lowercase, uppercase, digits, and special symbol. Please use a character array to store the input string. You can assume the character array is large enough to store all input characters. Also, write a program to test your function. - read and store the input string as a character array - a function to count the number of lowercase, uppercase, digits, and special symbol - a main function to call your function

Explanation / Answer

Answer in c language is below:

#include<stdio.h>

void count(char ch[])
{
    int upper = 0, lower = 0,digit=0,special=0;
    int i;
    for(i = 0; ch[i]!='';i++)
    {
        if (ch[i] >= 'A' && ch[i] <= 'Z')
            upper++;
        else if (ch[i] >= 'a' && ch[i] <= 'z')
            lower++;
        else if(ch[i] >='0' && ch[i] <='9')
            digit++;
        else if(ch[i]!='*' || ch[i]!='$' || ch[i]!='@' || ch[i]!='!' || ch[i]!='&' || ch[i]!='#' || ch[i]!='^')
            special++;
    }

    printf(" Uppercase Letters : %d", upper);
    printf(" Lowercase Letters : %d", lower);
    printf(" Digits : %d", digit);
    printf(" Special Characters : %d",special);

}

int main()
{
char ch1[80];
printf(" Enter The String : ");
gets(ch1);
count(ch1);
return 1;
}

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