Write MIPS code that sets bits 7 and 9 (makes them 1) in $t0. The code should pr

Question

Write MIPS code that sets bits 7 and 9 (makes them 1) in $t0. The code should preserve the contents of all other bits. (HINT: Use an “ori” operation) (Note: Only 1 line is necessary)

Write MIPS code that clears bits 11 and 13 (makes them 0) in $t0. The code should preserve the contents of all other bits. . (HINT: Use an “andi” operation) (Note: Only 1 line is necessary)

Write MIPS code that prints "It is negative" when the value in register $t1 is less than 0.

.data

negative:   .asciiz "It is negative"

.text

li $t1, -30 ##<--Note $t1 is set to a negative

### your code goes here ###

Explanation / Answer

Question:1

## ori makes an OR operation on 2nd and 3rd arguments and store the result in 1st argument
## 3rd argument should be immediate data from ori
## OR operation with 1 sets the bit
ori $t0, $t0, 101000000 ## 7th and 9th bits from right are set to 1.

Question 2:

## andi makes an AND operation on 2nd and 3rd arguments and store the result in 1st argument
## 3rd argument should be immediate data from andi
## AND opearation with 0 clears the bit
ori $t0, $t0, 0101111111111 ## 11th and 13th bits from right are set to 0.

Question 3:
.data
negative: .asciiz "It is negative"
.text
li $t1, -30 ##<--Note $t1 is set to a negative
### your code goes here ###
bltz $t1, offset # Branch on less than zero. if value in $t1 is less than zero then branches to offset
li   $v0, 10           # system call code for exit is 10
syscall               # call operating sys
offset:
li   $v0, 4           # system call code for printing string is 4
la   $a0, negative   # load address of string to be printed into $a0
syscall  

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