See above figure which shows numbers-letters association used in phone keys. You

Question

See above figure which shows numbers-letters association used in phone keys. Your task is to
1- Keep those association in an array of struct, such as
A, 2
B, 2
C, 2
D, 3
...
...
Z, 9

You will build your array of struct with hard-coded values.

2- Ask user repeatedly a four-letter combination, and find corresponding numbers for the combination.

Once user enters CSCI

Your program should output 2724. Similarly,

ABCD should be map to 2232
TOMY should be map to 8669
GONE should be map to 4663

Exit the program if user enters EXIT.  

Now write a C++ program following above information.

Explanation / Answer

#include <iostream>
#include <string>

using namespace std;

struct key_map
{
   // char for each alphabet
   char ch;
   // int for number on keypad
   int n;
};

int main()
{
   // To store 4-letter word from user
   string input;
   // To store output value
   int output;
   // integers to use in loops
   int i, index;
   // array of structs
   key_map arr_key_map[] = {
       {'A', 2},
       {'B', 2},
       {'C', 2},
       {'D', 3},
       {'E', 3},
       {'F', 3},
       {'G', 4},
       {'H', 4},
       {'I', 4},
       {'J', 5},
       {'K', 5},
       {'L', 5},
       {'M', 6},
       {'N', 6},
       {'O', 6},
       {'P', 7},
       {'Q', 7},
       {'R', 7},
       {'S', 7},
       {'T', 8},
       {'U', 8},
       {'V', 8},
       {'W', 9},
       {'X', 9},
       {'Y', 9},
       {'Z', 9}   };
  
   // Ask user for 4-letter word
   cout << "Enter a four letter word : ";
   // Store the 4-letter word
   cin >> input;
   // Loop until EXIT word is received from user
   while(input != "EXIT")
   {
       // initialize output value to 0
       output = 0;
       // Loop over each letter of the word
   for(i=0;i<4;i++)
       {
           // search for the letter in the array of structs
           for(index = 0;index<26;index++)
           {
               if(input[i]==arr_key_map[index].ch)
               {
                   // multiply output by 10 and then add current letter's number
                   /* To append 5 to 3, we need to multiply 3 by 10 and then add 5
                   output = 3
                   output = 3*10 = 30
                   output = 30+5 = 35
                   */
                   output *= 10;
                   output += arr_key_map[index].n;
                   // beak out of for loop once the match is found
                   break;
               }
           }
       }
       // print the output value
       cout << "The Output is " << output << " ";
       cout << "Enter a four letter word : ";
       cin >> input;
   }
   return 0;
}

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