Most metals weaken as temperature increases. For many metals, its Ultimate Tensi

Question

Most metals weaken as temperature increases. For many metals, its Ultimate Tensile Strength (UTS) is defined by the following equation, where T is the current temperature and the Exponent is specific to the metal: UTS = 1.0 - (T/1000)^Exponent For example, a common type of Stainless Steel has an Exponent value of 2.0. For the temperature values [0, 100,200,300, 400, 500], the UTS of this type of stainless steel is [1.0, 0.99, 0.96, 0.91, 0.84,0.75]. That means, for example, that at 500 degrees C, this type of stainless steel retains 75% of its original strength. Write a function that takes 2 vectors, T and E --- temperatures and exponents -- and returns a matrix of UTS values for each combination of temperature and exponent. Example: suppose T= [0, 200, 400] and E [2.0, 3.0], then the function returns 1.0, 1.0 0.96, 0.992 0.84, 0.936 the rows denote each temperature [0,200,400] and the columns denote each exponent [2.0,3.0].

Explanation / Answer

As the language is not mentioned so I will be using JAVA to implement the function

The complete Java code is shown below. It contains a main method to intialize the two vectors and calcUTS method which alculates the UTS from the values passed through two arrays.

import java.util.*;
import java.io.*;

public class UltimateTensileStrength{

static void clacUTS(double temp[], int exp[])
{
       double uts;
       int s1=temp.length;
       int s2=exp.length;
      
       double utsArr[][]= new double[s1][s2];
       for(int i=0;i<s1;i++)
       {
           for(int j=0;j<s2;j++)
           {
               uts=1.0-Math.pow((temp[i]/1000),exp[j]);
               utsArr[i][j]=uts;
           }
       }
      
       for(int i=0;i<s1;i++)
       {
           for(int j=0;j<s2;j++)
           {
               System.out.print(utsArr[i][j]+" ");
           }
           System.out.println(" ");
          
       }
}
public static void main(String[] args) {
  
try
{
  
           double temp[]={0,200,400}; // Temperature Vector and size can be changed
           int exp[]={2,3};               // Exponents Vector and size can be changed
          
           clacUTS(temp,exp);
          

  
}
  
catch(Exception e)
{
System.out.println(e);
}
}
}

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