Find the error(s) in the following code fragments and explain how to correct it

Question

Find the error(s) in the following code fragments and explain how to correct it (them). Int g() {cout "Inside function g" endl; int h() {cout "Inside h" endl;}} int sum (int x, int y) { int result; result = x + y;} void product { int a, b, c, result; cout "Enter three integers: "; cin a b c; result = a*b*c; cout "Result is " result; return result; } double square (double n) {double n; return n*n;} float cube (float); // function prototype double cube (float number) // function definition{ return number*number*number; } const int N = 10; int a[N]; for(int i = l; i

Explanation / Answer

a.
error:function-definition is not allowed inside a function, before'{' token
   int h() {cout << "Inside h" << endl;}}

Correction:
int g() {cout << "Inside function g" << endl;}
int h() {cout << "Inside h" << endl;}
Note: These functions should not be placed inside main()

b.
error:function-definition is not allowed inside main(), before'{' token
   int sum (int x, int y) {int result; result = x + y;}

Note:
This error arises if the code fragment is inside the main()
Otherwise there is no error if it is written as the function outside(before) main()

Correction:
Place the code fragment as the function outside(before) main()

c.
error: return-statement with a value, in function returning 'void'
   return result;}
  
Correction:
int product ()

d.
error: declaration of 'double n' shadows a parameter
{double n; return n*n;}

Correction:
double square(double n)
{return n*n;}

e.
error: ambiguating new declaration of 'double cube(float)'   
double cube (float number)
                       ^
Correction:
double cube (float); //function prototype

f.
const int N=10;int a[N];for(int i=1;i<=10; i++) {cin>>a[i];}

error: as per the code you have to access a[10]
but as per array definition, a[10] => a[0] to a[9] are allowed.

Correction:
const int N=10;int a[N];for(int i=0;i<10; i++) {cin>>a[i];}

g.
const int N=2; int a[N]={2,3},b[N]={3,4},c[N]; c=a+b;
error: invalid operands of types 'int [2]' and 'int [2]' to binary 'operator+'
const int N=2; int a[N]={2,3},b[N]={3,4},c[N]; c=a+b;
                                                   ^
Correction:
const int N=2; int a[N]={2,3},b[N]={3,4},c[N]; for(int i=0;i<N;i++){ c[i]=a[i]+b[i];}
                                                     
Note: c[N]=a[N]+b[N];

works, syntax wise but does not give intended result.

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