I need to convert these two small program to c++ and provide with print screen f

Question

I need to convert these two small program to c++ and provide with print screen for the out put .

void fun(int*p) // pass by refernce
{
    int i;
    for(i=0;i<=100;i++)
    {
        printf("%d",*p);
        p++;

    }
}
void main()
{

    int arr[100] = {0,0};
    int i ;
    clock_t t;
    float t= clock();
    for(i=0;i<=10;i++)
    {
        fun(arr);
    }
    t=clock_t;
    cout<"process reterned 0 (0x0) excution time:"<<((float))t/CLOCKS_PER_SEC<<"s"<<endl;
}

the second one :

void fun(int p[100]) pass by value
{
     int i ;
     for(i=0;i<=100;i++)
     {
         printf("%d",p[i]);
     }
}
void main()
{
    int arr[100]={0,0};
    int i;
    clock_t t;
    t= clock();
    for(i=0;i<=10;i++)
    {
        fun(arr);
            t=clock_t;
    cout<"process reterned 0 (0x0) excution time:"<<((float))t/CLOCKS_PER_SEC<<"s"<<endl;
    }
}

the idea here to copmpare the time excution between two array one pass by value and the second one pass by reference in two separated program

Explanation / Answer

1.

#include<iostream>
using namespace std;
void fun(int*p);
int main()
{
int arr[100] = {0,0};
int i ;
clock_t t;
float t= clock();
for(i=0;i<=10;i++)
{
fun(arr);
}
t=clock_t;
cout<"process reterned 0 (0x0) excution time:"<<((float))t/CLOCKS_PER_SEC<<"s"<<endl;
}
void fun(int*p) // pass by refernce
{
int i;
for(i=0;i<=100;i++)
{
cout<<*p;
p++;

}
}

2.

#include<iostream>
using namespace std;
void fun(int p[100])
{
int i ;
for(i=0;i<=100;i++)
{
cout<<p[i];
}
}
int main()
{
int arr[100]={0,0};
int i;
clock_t t;
t= clock();
for(i=0;i<=10;i++)
{
fun(arr);
t=clock_t;
cout<"process reterned 0 (0x0) excution time:"<<((float))t/CLOCKS_PER_SEC<<"s"<<endl;
}
}

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