What does the following code prints out ? int y = 1; for (int x=-2; x < 8; x = x

this program does not compile because the syntax you are using for your program is wrong. It is giving complier error.

ID: 3769016 • Letter: W

Question

What does the following code prints out ?

int y = 1;

for (int x=-2; x < 8; x = x+2) {

y = x / y;

cout << y << " & ";

}

cout << " x=" << x;

int x = 5;

do {

if ( x % 2 == 0) x -= 2;

else x++;

cout << x << " + ";

} while (x >= 2 || x == -2);

int fun (int& x, int y, int z) {

x += (x + z);

y = 22;

cout << x << y << z; return 5;

}

int main( ) {

int x = 1, y = 7, &z = y;

z = fun(x, y, z);

cout << x << y << z;

}

char x[] = “ELET2300”; // ‘A’=65, ‘0’= 48

cout << x;

cout << x[1];

x[2] = x[5] + 1;

cout << x[2];

x[3] += 1;

cout << x;

cout << x[1] + x[4];

this program does not compile because the syntax you are using for your program is wrong.

It is giving complier error.

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