Assembly Language Write an assembler program to find the sum of the first n odd

Question

Assembly Language

Write an assembler program to find the sum of the first n odd integers starting from 1 (n is a positive integer) by using the pseudo-code below.

;n is greater than or equal to 0 – use db to define it

;result is in sum – use db to define sum

Get the value of n

counter = 1

j = 2

term = 1

sum = 0

back: if counter <= n then

sum = sum + term   

term = term + 2

counter = counter+1

          goto back

      else stop

            halt
n:         db 5
sum:    db 0

Note: In this example since n=5 then we will find the sum of first 5 odd integers starting from 1 which means:

1+3+5+7+9=25 (Result will be 19 in hexadecimal notation)

Explanation / Answer

Here is your program as per your requirements.

model small
.stack 200H
.data
msg1 DB 10,13,'Enter limit: $'
msg2 DB 10,13,'Enter the numbers: $'
msg3 DB 10,13,'Sum = $'
newline DB 10,13, ' $'
sum DW 0

.code
printstring MACRO msg ;macro definition

PUSH AX
PUSH DX
MOV AH,09H
MOV DX,offset msg
INT 21H
POP DX
POP AX
ENDM

.startup

printstring msg1   
CALL readnumtoAX ;enter the limit
MOV CX,AX ;cxlimit
printstring newline
printstring msg2
label1: printstring newline
CALL readnumtoAX ;enter the no.s
ADD sum,AX ;sum=sum+ax
DEC CX ;cxcx-1
JNZ label1
printstring newline
printstring msg3 ;print sum
MOV AX,sum
CALL displayAX

.exit

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