Good evening master programmer Can you solve problem 2 and 3 I will see what I d

Question

Good evening master programmer Can you solve problem 2 and 3 I will see what I did wrong And learn from you master! Thank u Question 2. Use the standard template library vector.h to implement the followings. (Lecture 19) Step 1. Create a vector including numbers 1.1, 2.2, 3.3, 4.4, 5.5 6.6, 7.7, 8.8, 9.9, 1.1, 2.2, 3.3. Display the contents. Step 2. Randomly shuffle the vector's contents. Display the contents Step 3. Sort the vector's elements. Display the contents. Step 4. Search for number 3.3, and display whether it is found in the vector. Step 5. Display the count of number 1.1 in the vector. Step 6. Find the Maximum and Minimum value of the vector and display them. Step 7. Calculate OneHundred TimesPlusOne of the vector and display the result. Question 3. Make a template out of the following file and test on different data types, including int, double and string. (Lecture 18) #include Kiostream> #include

Explanation / Answer

Solution for question 3:

#include <iostream>

template<typename T> T myMax(T one, T two)

{

   T bigger;

   if(one < two)

   {

       bigger = two;

   }

   else

   {

       bigger = one;

   }

   return bigger;

}

int main()

{

   int i_one = 3, i_two = 5;

   cout<<"The max of "<<i_one<<" and "<<i_two<<" is "<<myMax(i_one, i_two)<<endl;

   double d_one = 6.7, d_two = 3.4;

   cout<<"The max of "<<d_one<<" and "<<d_two<<" is "<<myMax(d_one, d_two)<<endl;

   string s_one = "hi", s_two = "hey";

   cout<<"The max of "<<s_one<<" and "<<s_two<<" is "<<myMax(s_one, s_two)<<endl;

}

OUTPUT:

The max of 3 and 5 is 5

The max of 6.7 and 3.4 is 6.7

The max of hi and hey is hi

Solution for question 2

/*

* main.cpp

*

* Created on: 26-Nov-2016

* Author: kasturi

*/

#include <iostream>

#include <vector>

#include <algorithm>

using namespace std;

//using a function to print the elements of the vector into the console

void print(vector<float> &items)

{

   for (std::vector<float>::iterator it = items.begin() ; it != items.end(); ++it)

      std::cout << *it<< ' ' ;

      std::cout << ' ';

}

int main()

{

   //declaring a vector

   vector<float> vector;

   float num = 1.1;

   //adding values into vector . You can one after the other or through for loop.

   for(int i=1; i<=9; i++)

   {

       vector.push_back(num);

       num = 1.1 * (i+1);

   }

   vector.push_back(1.1);

   vector.push_back(2.2);

   vector.push_back(3.3);

   //printing the vector

   print(vector);

   //using built-in random shuffle function to shuffle the elements of the vector

   random_shuffle(vector.begin(), vector.end());

   //printing the vector after shuffling

   print(vector);

   //sorting the vector

   sort(vector.begin(), vector.end());

   //printing the vector after sorting

   print(vector);

   bool isValuePresent = false;

   int counter = 0;

   for (std::vector<float>::const_iterator it = vector.begin() ; it != vector.end(); ++it)

   {

       if(*it == 3.3)

           isValuePresent = true;

       if(*it == 1.1)

           counter++;

   }

   if (isValuePresent)

           cout<<"3.3 is found"<<endl;

   else cout<<"3.3 is not found"<<endl;

   cout<<"Count of 1.1 is "<<counter<<endl;

   float max = *max_element(vector.begin(), vector.end());

   cout<<"Maximum element is "<<max<<endl;

   float min = *min_element(vector.begin(), vector.end());

   cout<<"Minimum element is "<<min<<endl;

   return 0;

}

OUTPUT:

1.1 2.2 3.3 4.4 5.5 6.6 7.7 8.8 9.9 1.1 2.2 3.3

7.7 2.2 8.8 5.5 1.1 9.9 1.1 3.3 2.2 4.4 3.3 6.6

1.1 1.1 2.2 2.2 3.3 3.3 4.4 5.5 6.6 7.7 8.8 9.9

3.3 is found

Count of 1.1 is 2

Maximum element is 9.9

Minimum element is 1.1

// I didnt get what oneHundredTimesPlusOne meant, So didnt implement that.. let me know and will do it.

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