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Let S be a set of n points in the plane. A split tree is a special binary tree t

ID: 3784080 • Letter: L

Question

Let S be a set of n points in the plane. A split tree is a special binary tree that stores all the points in S. The root of the split tree stores the point p with the median r-coordinate among all points in S. This splits S into two sets, Sieh and Sight, which consist of the points to the left and right of p, respectively. The left child is a split tree on Sien and the right child is a split tree on Sighr. But there is a twist: their root stores the point with the median y-coordinate and splits the rest of the points based on their y-coordinate, not a-coordinate. The direction of the split alternates with each level. See Figure 2 for an example. are indicated in blue, while horizontal splits (on y-coordinate) are red.

Explanation / Answer

#include<iostream>

#include <list>

using namespace std;

// This class represents a directed graph using adjacency list representation

class Graph

{

    int V;    // No. of vertices

    list<int> *adj;    // Pointer to an array containing adjacency lists

public:

    Graph(int V); // Constructor

    void addEdge(int v, int w); // function to add an edge to graph

    void BFS(int s); // prints BFS traversal from a given source s

};

Graph::Graph(int V)

{

    this->V = V;

    adj = new list<int>[V];

}

void Graph::addEdge(int v, int w)

{

    adj[v].push_back(w); // Add w to v’s list.

}

void Graph::BFS(int s)

{

    // Mark all the vertices as not visited

    bool *visited = new bool[V];

    for(int i = 0; i < V; i++)

        visited[i] = false;

    // Create a queue for BFS

    list<int> queue;

    // Mark the current node as visited and enqueue it

    visited[s] = true;

    queue.push_back(s);

    // 'i' will be used to get all adjacent vertices of a vertex

    list<int>::iterator i;

    while(!queue.empty())

    {

        // Dequeue a vertex from queue and print it

        s = queue.front();

        cout << s << " ";

        queue.pop_front();

        // Get all adjacent vertices of the dequeued vertex s

        // If a adjacent has not been visited, then mark it visited

        // and enqueue it

        for(i = adj[s].begin(); i != adj[s].end(); ++i)

        {

            if(!visited[*i])

            {

                visited[*i] = true;

                queue.push_back(*i);

            }

        }

    }

}

// Driver program to test methods of graph class

int main()

{

    // Create a graph given in the above diagram

    Graph g(4);

    g.addEdge(0, 1);

    g.addEdge(0, 2);

    g.addEdge(1, 2);

    g.addEdge(2, 0);

    g.addEdge(2, 3);

    g.addEdge(3, 3);

    cout << "Following is Breadth First Traversal "

         << "(starting from vertex 2) ";

    g.BFS(2);

    return 0;

}

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