In Figure 4.3(c), network addresses 172.16x.0 are subnets derived from the netwo
ID: 3785241 • Letter: I
Question
In Figure 4.3(c), network addresses 172.16x.0 are subnets derived from the network address 172.160.0. Explain how IP address bits are split between subnet and host addresses.
Okay, so I know that the 172 part is the over arching network. What I don't understand is
A. Is the over arching network 172 or 172.160?
B. Likewise, is the subnet 172.16.x or 172.160.x?
I get that in an IP address, let's say its 192.168.1.12 that the 192 indicates the class (in this example Class C). Does that mean that the 168.1 is a subnet?
I'm not sure how to answer the question. I'd guess that the address bits are split as 172.16(network).46(subnet).3(host) but I'm not sure if that's right. I'm having a hard time grasping this one.
Title: Addresses: 172.16.46.2 Name or IP Address: 172.16.46.2 Index interface IP Address Network Mask Network Address Link Address 265.255.255.0 172.1646.0 1 3Com 172.16.46.2 0x08004E07 C25C 2 3Com 192.168.101.1 265.255.255.0 192.168 101.0 knone (a) Addresses on 172.16.46.2 Hub Ports Title: Addresses: 172.16.46.3 Name or IP Address: 1 72.16.46.3 Index Interface IP Address Network Mask Network Address Link Address 1 3Com 172.16.463 255.255.255.0 17216 46.0 0x08004E09 19D4 2 3Com 192168 101.1 255.255.255.0 192.168.101.0Explanation / Answer
First of all you must understand that IP addresses (32 bits) are divided into three broader classes:
class A: (range from 0 to 127) in which starting 8 bits are network id and 24 bits are host id
class B: (range from 128 to 191) in which starting 16 bits are network id and 16 bits are host id
class C: (range from 192 to 223) in which starting 24 bits are network id and 8 bits are host id
Along with that you also need to understand due to limitations of public networks each switching device (Hub, switch or router) assign private networks to the hosts connected to them. For class C, 192.168.0.0 - 192.168.255.255 is range of private address.
Hope this gives you a little bit idea about the networking. Now, coming to your questions:
A.) 172.16.0.0 is over-arching network
B.) 172.16.x.0 is subnet id
c.) No, 168.1 is not a subnet it's a part of network id.
Hope it helps, do give your response.
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