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Please correct my code below: class Node: def __init__(self, data): self.data =

ID: 3789399 • Letter: P

Question

Please correct my code below:

class Node:
def __init__(self, data):
self.data = data
self.adj = []
self.visited = False
  
def adjNode(self, new_adj_node):
self.adj.append(new_adj_node)
  
  

r = Node('r')
u = Node('u')
y = Node('y')
t = Node('t')
x = Node('x')
z = Node('z')
q = Node('q')
w = Node('w')
s = Node('s')
v = Node('v')


r.adjNode(u)
r.adjNode(y)
u.adjNode(y)
y.adjNode(t)
y.adjNode(q)
t.adjNode(x)
x.adjNode(z)
t.adjNode(y)
z.adjNode(q)
q.adjNode(w)
q.adjNode(s)
q.adjNode(t)
w.adjNode(s)
s.adjNode(v)

def dfs(r):
stack = []
stack.append(r)
  
while(len(stack>0)):
r=stack.pop()
if r=None:
stack.append(u)
if y!=None:
stack.append(t)
  

dfs(r)

Write the program to show how depth-first search works on the following graph. Assume that the DFS procedure considers the vertices in alphabetical order, and assume that each adjacency list is ordered alphabetically. Show the discovery and finishing time for each vertex. [10 pts] a

Explanation / Answer

#include<stdio.h>
#include<stdlib.h>

typedef struct node
{
struct node *next;
int ver;
}node;

node *G[20];   
int visitednode[20];
int n;
void read_graph();
void insert(int,int);

void DFS(int);

void main()
{
int i;
read_graph();

for(i=0;i<n;i++)
visitednode[i]=0;

DFS(0);
}

void DFS(int i)
{
node *p;

printf(" %d",i);
p=G[i];
visitednode[i]=1;
while(p!=NULL)
{
i=p->ver;

if(!visitednode[i])
DFS(i);
p=p->next;
}
}

void read_graph()
{
int i,vi,vj,no_of_edges;
printf("Enter number of vertices:");

scanf("%d",&n);

for(i=0;i<n;i++)
{
G[i]=NULL;


printf("Enter number of edges:");
scanf("%d",&no_of_edges);

for(i=0;i<no_of_edges;i++)
{
printf("Enter an edge(u,v):");
scanf("%d%d",&vi,&vj);
insert(vi,vj);
}
}
}

void insert(int vi,int vj)
{
node *p,*q;
  
q=(node*)malloc(sizeof(node));
q->ver=vj;
q->next=NULL;

if(G[vi]==NULL)
G[vi]=q;
else
{
p=G[vi];

while(p->next!=NULL)
p=p->next;
p->next=q;
}
}

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