Part of the function has been given and I have to use the given codes to deal wi

Question

Part of the function has been given and I have to use the given codes to deal with the question.

Can't understand why the first one is wrong and third one is correct.

Thanks for help!

32/CSE 42 Fall 2016, UC Inine oblem 2 (6 points) rte a Python function square-all that takes one parameter, a nested list of integers, and retums a ew nested list of integers that is structurally identical to the given list, but in which all of the integers ave been squared. Note that the function should not modify its parameter: it should build a new, eparate list. complete the function by writing anything you think is needed above, within, or below the loop. Do not write code outside of the function. Assume that there are no global variables available to you. Do not make changes to the code that has been provided. It is not necessarily the case that every blank space needs code. A doc string is not required. Here is a non-exhaustive list of examples of how the function should behave when it's flnished: square all([1, 2, 31) [1, 4, 9] square all([4, [6, 8], 18, [12]])) 116, [36, 64], [18e, [144]] square all def square all(nuns: nested list of integers") 'nested list of integers for x in nums: ere a ll (a). else

Explanation / Answer

to find the square of all elements in list or arrray numpy.square is very helpful.

>>> import numpy as squareall

>>> square_list = [1,2,3,4]

>>> squareall.square(square_list)

array([1,4,9,16])

like the same way we can mention power of the array.

numpy.power()

so we can modify the above code segment

squareall.power(square_list,2) here 2 is power

and it prints the squre list of the array.

>>>square_all([1,2,3])
[1,4,9]

>>>square_all([4,[6,8],[10,[12]]])

[16,[36,64],[100,[144]]]

>>aquare_all([])

The above are three different scenarios

1st scenario is plian array here we apply the function square then it prints the array of square

2nd scenario has nested list or array

so it go to each arraylist and quaring it and go to each elecment in side the array.

so the function definitiuon is like
def square_all(nums: 'nested list of integers')

Note: the question image first one is clear but not second.

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