Can use help with scripting in Linux/UNIX, using the sed command: Consider the a
ID: 3792160 • Letter: C
Question
Can use help with scripting in Linux/UNIX, using the sed command:
Consider the address book below:
$ cat addr
Xiao Li, lxiao@unc.edu, 6705462234, Jackson, NC 764
Natkin William, wnatkin@imap28.vcu.edu, 8044344528, Richmond, VA 22345 Elizi Moe, emoe@ncsu.edu, 5208534566, Tempe, AZ 85282
Ma Ta, mta@yahoo.com, 4345667345, Austin, TX 91030
Diana Cheng, dcheng@asu.edu, 5203456789, Matitsi, WY 4587
Jackson Five, jfive@ncsu.edu, 5206564573, Kyenta, AZ 85483
Adi SrikanthReddy, sadi1@imap1.asu.edu, 6578904566, Wyo, WS 67854
Part 1: Print the lines with imap number in the email address. (using sed)
Part 2: Print the lines that end with valid zip code (using sed)
Part 3: Print the lines that end with invalid zip code (using sed)
Explanation / Answer
part1
>sed -n '/imap/ p' file.txt
Change the filename
Or for searching a pattern we can use:
sed 's/pattern/' file.txt
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