Help with this computer network question, please! A file of size 200 MB (assume

Question

Help with this computer network question, please!

A file of size 200 MB (assume 1MB = 10^6 bytes), is to be sent over a packet-switched network in which each packet carries a header of size 25 bytes and a maximum payload of 2000 data bytes. The path from the source to the destination consists of 4 links. Each link has a transmission rate of 200 Mbps and a propagation delay of 4 msec. You may ignore processing and queuing delays. Find the total end-to-end delay for sending one packet from the source to the destination. For the file of size 200 MB, how many packets are transmitted by the source? Find the total end-to-end delay for sending the entire file from the source to the destination. Is your answer for part (c) equal to the product of your answers for parts (a) and (b)? Explain why or why not.

Explanation / Answer

b)

Total file size = 200MB = 200*10^6 bytes

Payload per packet = 2000 bytes

No of packets = total file size / payload per packet

= 10^5 packets

a)

Since one packet is max of 2000 bytes it can be sent over a single link in one second

Then total end to end delay for one packet = 4msec

c)

If we use 4 links ,then for 1 second/1time we can send

200*4 = 800 MB data with a propagation delay of 4msec in total.

d) no answer c is not product of a and b because ,200MB can be transferred in the form of 10^5 packets in one second using the 4 200MBps links. this is achieved by parallel transmission. hence transmission delay is also parallel. hence it is 4msec in total as all the packets can transferred at one instant.

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