please tell me why the code print out that in the console Q1. Consider the follo

Question

please tell me why the code print out that in the console

Q1. Consider the following code public class ABC private static int count private int x; public ABC (int i) public void incrementCount Count public void print X System out.println ("Value of x x) i public static void printCount System. out.println ("Value of count count) public static void main (String C] args) ABC demo new ABC (5) ABC Obj 1 new ABC (2) ABC Obj 2 new ABC (5) Obj 1. printX O; Obj 1. increment Count demo. increment Count obj1. Count o; print, Obj2.print Count

Explanation / Answer

First of all static means it declears only single time .

Here is step by step execution that how it prints?

public static void main(String []args){
ABC demo = new ABC(5);
ABC Obj1 = new ABC(2);
ABC Obj2 = new ABC(5);
Obj1.printX(); //print x value of Obj1 output is 2
Obj1.incrementCount(); // increments the count to 1
demo.incrementCount(); // increments the count to 2
Obj1.printCount(); // prints the count output is 2
Obj2.printCount(); // prints the count output is 2
Obj2.printX(); // print the value of x in Obj2 . output is 5
Obj1.incrementCount(); // increments the count to 3
Obj1.printX(); // print the value of x in Obj1 . output is 2
Obj1.printCount(); // prints the count output is 3
Obj2.printCount(); // prints the count output is 3
}

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