Consider the following RDF graph in Turtle format: @prefix rdf: chttp://www.w3.o

Question

Consider the following RDF graph in Turtle format: @prefix rdf: chttp://www.w3.org/1999/02/22-rdf-syntax-ns#>. @prefix rdfs: . @prefix xsd: chttp://www.w3.org/2001/XMLSchema#>. @prefix schema: . @prefix dbr: chttp://dbpedia.org/resource/>. @prefix dbo: chttp://dbpedia. org/ontology/>. @prefix movie: Chttp://data. linkedmdb. org/resource/movie/>. @prefix dc: chttp://purl. org/dc/terms/>. dbr:Bill_Murray dbo:birthName "William James Murray"Sen; movie:star_of "Ghostbusters"@en, "Scrooged"@en; rdf:type schema:Person. dbr:Richard.Donner dbo:birthName "Richard Donald Schwartzberg"@en; rdf:type schema:Person. dbr:Ivan_Reitman dbo:birthName "Ivan Reitman"®en; rdf:type schema:Person. Write a SPARQL query without prefixes that returns birth names of all people who starred in a movie. To save time, you may refer to the URIs above as where X is the corresponding line number.

Explanation / Answer

select ?birthname

where

{

?x dbo:birthname ?birthname

?x movie:star_of : Ghostbusters

}

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