The following code segment is a count-controlled loop going from 1 through 5. At

Question

The following code segment is a count-controlled loop going from 1 through 5. At each iteration, the loop counter is either printed or put on a stack depending on the Boolean result returned by the method random. (Assume that random randomly returns either true or false.) At the end of the loop, the items on the stack are removed and printed. Because of the logical properties of a stack, this code segment cannot print certain sequences of the values of the loop counter. You are given an output and asked to determine whether the code segment could generate the output. for (count = 1: count

Explanation / Answer

Answer a)

output possible 1, 3, 5, 2,4

Count 1 random() = True , print 1

Count 2 random () = False,

Count 3 random() = True, print 3

Count 4 random() = False,

Count 5 random() = True, print5

While loop print :- 4,2

so output will be : 1,3,5,4,2

Flase

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b)

output possible 1, 3, 5, 4, 2

Count 1 random() = True , print 1

Count 2 random () = False,

Count 3 random() = True, print 3

Count 4 random() = False,

Count 5 random() = True, print5

While loop print :- 4 ,2

so output will be : 1,3,5,4,2

TRUE

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c)

output possible 1, 3, 5, 2,4

Count 1 random() = True , print 1

Count 2 random () = False,

Count 3 random() = True, print 3

Count 4 random() = False,

Count 5 random() = True, print5

While loop print :- 2 ,4

so output will be : 1,3,5,2,4

TRUE

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b)

output possible 1, 2, 3, 4, 5

Count 1 random() = True , print 1

Count 2 random () = True, print 2,

Count 3 random() = True, print 3

Count 4 random() = True, print 4

Count 5 random() = True, print5

so output will be : 1,2,3,4,5

TRUE

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D)

output possible 5, 4, 3, 2, 1

Count 1 random() = False ,

Count 2 random () = False

Count 3 random() = False ,

Count 4 random() = False ,

Count 5 random() = False ,

While loop print 5,4,3,2,1

so output will be : 5,4,3,2,1

TRUE

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If you have any query, please feel free to ask.

Thanks a lot.

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