C Programming /* This program will be called with one command line argument that

Question

C Programming

/*
This program will be called with one command line argument that
contains a string followed by an asterisk and an integer. Print
out the string as many time as indicated by the integer. For
example, when called as prog Hi*3, you print HiHiHi.

Hint: Look for the '*' starting from the back of the string.
len = strlen(arg) gives you the string length.
When you have found the '*', then arg + len + 1 is a pointer
to the integer that you can pass to atoi as in the preceding
exercise. Replace the '*' with a '' so you can print the
part that precedes it.
*/

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(int argc, char* argv[])
{
   int count = 1;
   char* arg;
   int len;
   if (argc < 2) return -1;
   arg = argv[1];
   len = strlen(arg) - 1;
   ...
   for (int i = 0; i < count; i++)
      printf("%s", arg);
   printf(" ");
   return 0;
}

Explanation / Answer

This tis the proper working code.

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <string.h>

int main(int argc, char* argv[])
{
int number, count = 0;
char* arg;
int len;
if (argc < 2)
   return -1;
arg = argv[1];
int stringLength = strlen(arg);
len = stringLength-1;
while(arg[len]!='*')
   len--;
printf("%d", len);
number = atoi(arg + len+1);
printf(" %d", number);
arg[len] = '';
for (int i = 0; i < number; i++)
printf("%s", arg);
printf(" ");
getch();
return 0;
}

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