Consider the following code: int main(int argc, char* argv[]) {char buf[] = \"ab

ID: 3795151 • Letter: C

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Consider the following code: int main(int argc, char* argv[]) {char buf[] = "ab"; int r = open("file.txt", 0_RDONLY); int r1, r2, pid; r1 = dup(r); read(r, buf, 1); if((pid = fork()) = 9); {r1 = open("file.txt", 0_RDONLY);} else{waitpid(pid, NULL, 0);} read(r1, buf, 1); printf("%s", buf); return 0;} Assume that the disk file "file.txt" contains the string of bytes 15213. Also assume that all system calls succeed. What will be the output when this code is compiled and run and why? Explain your answer by providing a high level description of the code functionality.

Explanation / Answer

It will print some random value.

In my case the file.txt contains "ankit" string..

and it is printing abnb..

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Consider the following code: int main (int argc, char* argv[]) {char buf[] = \"a

Consider the following code: int sum(int a, int& b) { b += 5; a += 3; return a+b

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Consider the following code: int main(int argc, char* argv[]) {char buf[] = \"ab

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