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For the following questions, consider a paged memory system that has a physical

ID: 3797463 • Letter: F

Question

For the following questions, consider a paged memory system that has a physical main memory size of 64KB (2^16) and a page frame size of 8KB (2^13). Consider a process P whose logical address space is 64KB (2^16).

Question 1: How many physical page frames are there in the above paged memory system? ________(Your answer should be in exponential form)

How many bits are needed to represent a physical page frame number in the system? ___________

Question 2: How many logical pages are there for P? _______________(Your answer should be in exponential form.)

   How many bits are needed to represent a logical page number for P? _______________

Could someone please help me. I don't understand.

Explanation / Answer

1) The number of physical page frames are there in the above paged memory system is
2^16 / 2^13 . = 2^3 = 8

So there are Eight physical page frames are there in the above paged memory system

And we know for 8 frames we require them to represents then in 3 bits





2) Logical address is divided into page number and the offset within the page.

Same as above , 2^16 / 2^13 --> 3 bits necessary to adress which page and 13 bit needed for the offset


How many logical pages are there for P : Same 8
3 bits are needed to represents represent a logical page number for P


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