Let f (n) and g(n) be functions mapping nonnegative integers to real numbers. We
ID: 3798305 • Letter: L
Question
Let f (n) and g(n) be functions mapping nonnegative integers to real numbers. We say that f (n) is (g(n)) if there is a real constant c > 0 and an integer constant n0 1 such that for all n n0 , f (n) c g(n). Show that n2 is (nlog n) by specifying the constants c and n0 Let f (n) and g(n) be functions mapping nonnegative integers to real numbers. We say that f (n) is (g(n)) if there is a real constant c > 0 and an integer constant n0 1 such that for all n n0 , f (n) c g(n). Show that n2 is (nlog n) by specifying the constants c and n0 Let f (n) and g(n) be functions mapping nonnegative integers to real numbers. We say that f (n) is (g(n)) if there is a real constant c > 0 and an integer constant n0 1 such that for all n n0 , f (n) c g(n). Show that n2 is (nlog n) by specifying the constants c and n0Explanation / Answer
for n 1
n > logn
Multiplying with n on both sides
n2 > nlogn
So for c = 1 and n0 = 1, we have proved that n2 is (nlogn)
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