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This is for a beginners C++ class Assignment : Create a program which is capable

ID: 3799326 • Letter: T

Question

This is for a beginners C++ class

Assignment: Create a program which is capable of assembling and displaying various sets I will provide you with. The program must correctly display the result of operators on sets (such as Union and Intersection), and in addition it must do the following two things: First, it must NOT repeat any values that might appear more than once. So if you Union two sets together that each have the number ‘5’ somewhere in them, then ‘5’ should only appear ONCE in the resulting set. Second, if the resulting thread is empty, your program must indicate the empty thread in some recognizable manner, such as displaying “Empty Thread” or “E” or something similar. Below are the threads you will use. Also assume that the A group comprises ‘reality’ so to speak, the numbers 1-10 being all elements possible, such that the INVERSE of A, is the empty thread. Thus if you were asked to compute the INVERSE of B, it would be equivalent to saying “Set A minus Set B”. For this exercise, we will represent inverse with the ! symbol.

A = {1,2,3,4,5,6,7,8,9,10}

B = {2,4,6,8,10}

C = {1,3,5,7,9}

D = {1,2,3,5,7}

Problem 1.) A n D

Problem 2.) ( B U C ) n  A

Problem 3.) (!C U C) n  A

Problem 4.) A – D

Problem 5.) N(!A  U ( C U  D))

Problem 6.) B n  C

Problem 7.) N(B n C)

Problem 8.) A U B U C U  D

A reminder, N() indicates the SIZE of the resulting set. So if you have a set such as A = {1,3,7,10} then N(A) = 4. For problems asking for N(), your result should be a single number indicating the resulting set’s size. Finally, a basic hint to help with this assignment: You may find arrays to be useful

Explanation / Answer

since all the problems are for intersection or union i'll provide codes for them seperately, just use them in the order required through basic maths for set theory.

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for intersection

code-

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sort both the arrays (here array 1 and array 2)

then use the following code -

***the intersection array now holds the intersection of the 2 arrays.

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for union

code-

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again sort the two arrays, then use the code -

***union array now holds the union of the arrays!

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thank you

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