Here\'s some \"low-quality code given to me: void foo (int x) int a [3]; char bu

Question

Here's some "low-quality code given to me:

void foo (int x) int a [3]; char buf [4] a 11 gets (buf); print f ("a 0 0x x, a [1] Oxsx, buf s n", a [01, a C1), buf) In a program containing this code, procedure foo has the following disassembled form: LCO: string "a [0] 0x x, a [1] 0x x, buf s n" foo push %rbx subg $16, srsp Gedi, sebx movl &rsp; %rdi nova call gets &rsp; orCX nova movl Sebx, oedx movl $-2525 79085 se si movl LCO oedi movl 0, eaX printf call addq 16 "orSp Srbx popq ret For the following questions, recall that: gets is a standard C library routine. x86-64 machines are little-endian. C strings are null-terminated (i.e., terminated by a character with value 0x00). Characters '0' through '9' have ASCII codes 0x30 through 0x39.

Explanation / Answer

Answer A:

Answer B-

0xF0F1F2F3

x

01

Answer C:

Using pointers array can be allocated on the stack. Answer will not change but complexity of execution will change.

Program Value Decimal Offset a -12 Y a[2] -4 Y x +8 N buf -16 Y buf[3] -13 Y Saved value of register %rbx -20 N

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