Write a program which asks for the following information: bullet the date bullet

Question

Write a program which asks for the following information: bullet the date bullet the name of the person who the check is for bullet the amount of the check Using this information you should display a check formatted exactly like the example. The cash amount should be formatted to two decimal places. Input Validation: Do not accept values greater than 5,000. Do not accept negative amounts. A check for only a cents amount should be valid. Sample Output: What is the amount of the check?: 1920.85 Enter the date of the check: 1/21/2015 Who is the check for?: John Smith Date: 1/21/2015 Pay to the Order of: John Smith $1920.85 One thousand nine hundred twenty and 85 cents

Explanation / Answer

#include <stdio.h>
#include <string.h>
void convert_to_words(char *num, char *fraction)
{
    int len = strlen(num);
    char *single_digits[] = { "zero", "one", "two", "three", "four",
                              "five", "six", "seven", "eight", "nine"};

    char *two_digits[] = {"ten", "eleven", "twelve", "thirteen", "fourteen",
                     "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"};

    char *tens_multiple[] = {"", "", "twenty", "thirty", "forty", "fifty",
                             "sixty", "seventy", "eighty", "ninety"};
    char result[200] = {''};
    if (len == 4) {
        // get thousand place
        if (num[0] != '0') {
                strcat (result, single_digits[num[0] - 48]);
                strcat (result, " thousand ");
        }
        num++;
        len--;
    }
    if (len == 3) {
        // get hundred place
        if (num[0] != '0') {
            strcat (result, single_digits[num[0] - 48]);
                strcat (result, " hundred ");
        }
        num++;
        len--;
    }
    if (len == 2) {
        // if num >= 20 then this case
        if (num[0] > '1') {
            strcat (result, tens_multiple[num[0] - 48]);
            strcat (result, " ");
        } else if (num[0] == '1') { // if 2nd place is < 20 then only one word required
            strcat (result, two_digits[num[1] - 48]);
            num++;
            len --;
        }
        num++;
        len--;
    }
    if (len == 1) {
        // get ones place
        if (num[0] != '0')
            strcat (result, single_digits[num[0] - 48]);
    }
    if (strlen(result))strcat (result, " and ");
    printf("%s%s cents ", result, fraction);
}

int strtoint(char *input) {
    int res = 0;
    int i;
    for (i = 0; i < strlen(input); i++) {
        res = res * 10 + (input[i] - 48);
    }
    return res;
}

int is_valid(char *input, char *fraction) {
    if (strlen(input) > 0 && input[0] == '-') return 0;   // case of negative
    int num = strtoint(input); // convert string to int
    //if num > 5000 or number == 5000 anf fraction part is not 0 invalid
    if (num > 5000 || num == 5000 && strtoint(fraction) > 0) return 0;
    return 1;
}
void remove_trailing(char *input) {
    int len = strlen(input) - 1;
    while (len >= 0 && input[len] == ' ') input[len--] = '';
}
int main() {
    int i, len;
    char *fraction = NULL;
    char input[20];
    char name[30];
    char date[12];
    printf("What is the amount of check?:");
    fgets(input,20, stdin);
    remove_trailing(input);
    printf("Enter the date of the check:");
    fgets(date,12, stdin);
    remove_trailing(date);
    printf("Who is the check for?:");
    fgets(name,30, stdin);
    remove_trailing(name);
    len = strlen(input);
    for (i = 0; i < len; i++) {
        if (input[i] == '.') {
             fraction = input + i + 1;
             input[i] = '';
             break;
        }
    }
    if (!fraction) fraction = "0";
    if (!is_valid(input, fraction)) {
        printf("Enter amount in between 0.00 to 5000.00 cents");
        return 0;
    }
    printf(" Date: %s ",date);
    printf("Pay the order of: %s %s.%s ", name, input, fraction);
    convert_to_words(input, fraction);
    return 0;
}

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