Only Solve Part 3!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Question

Only Solve Part 3!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Part 1: Please write the function declaration (only the declaration, no definition) and 1-2 lines of code after that giving an example of client code calling that function. Please pay special attention to the parameters and their types, whether they are passed by value or by reference, and the return type. If the value of the parameter is numeric and the number does not have to be a whole number, double should be given preference over int.

e.g:
double add (double a, double b);
double total = add(2, 3);

1) A function named minVal which takes two numbers and returns the min of the two.
2) A function named inRangeLoHi which takes three parameters lo, hi, and val and returns whether or not val is in the range [lo, hi]
3) A function named isVowel which takes a letter and returns whether or not that letter is a vowel.
4) A function named letterAfter which takes a letter and a number n and returns the letter in the alphabet n positions after that letter
(z wraps back to a).
5) A function named displayGreeting which displays some constant greeting to the user.
6) A function named incrementAll which takes 3 numbers and increments each by one.
7) A function named getInput which takes 2 numbers as parameters and asks the user to provide values for those two numbers.

Part 2: Please describe very briefly (2-3 lines) if the clients of the functions need to know their definition to be able to use them. Why or why not?

Part 3: Assuming the functions in Part 1 exist, write a function (definition) called inRange which takes two numbers end1 and and end2 and a number val and returns whether val is in the range defined by [smallerEnd, higherEnd] depending on whether end1 or end2 is smaller. Your function must rely on existing functions above to do its work and it should do as little work of its own as possible.

Explanation / Answer

Hi,

int function inRange (int end1, int end2, int val){

int sum,smallerEnd,higherEnd;

sum=end1+end2;

//using the existing function to select min

smallerEnd= minVal(end1,end2);

higherEnd=sum-smallerEnd;

//calling the existing function of part1 which will do all the work

return inRangeLoHi (inRangeLoHi ,higherEnd,val);

}

Hi,

we can do the above program in c using just one condition like

lower end<val<upper end we can return 1 .Because the value will be in range.But in the question it was asked to use existing functions so i have done like that. you have any doubts please comment below.

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