Can anyone help me this. Please write the answer in Assembly language (software
ID: 3804692 • Letter: C
Question
Can anyone help me this. Please write the answer in Assembly language (software I used http://www.hvrsoftware.com/download.htm version1.08)
Write a program to count the number of occurrences of two consecutive zeros (00) or two consecutive ones (11) in a 16-bit data. The 16-bit data is the concentation of the two 8-bits from memory locations $D500 and $D501, where the most significant byte (MsB) of the 16-bit data is from SD500. The count is saved in memory location SD502, where the first 4-bits indicate the number For example, the count for the 16- data (1101001 l 101 10010) in SD502 should be 32.Explanation / Answer
Answer:
Assembly Language Code :
__gnu_cxx::__promote_2<int, int, __gnu_cxx::__promote<int, std::__is_integer<int>::__value>::__type, __gnu_cxx::__promote<int, std::__is_integer<int>::__value>::__type>::__type std::pow<int, int>(int, int):
push rbp
mov rbp, rsp
sub rsp, 16
mov DWORD PTR [rbp-4], edi
mov DWORD PTR [rbp-8], esi
pxor xmm1, xmm1
cvtsi2sd xmm1, DWORD PTR [rbp-8]
pxor xmm0, xmm0
cvtsi2sd xmm0, DWORD PTR [rbp-4]
call pow
movq rax, xmm0
mov QWORD PTR [rbp-16], rax
movsd xmm0, QWORD PTR [rbp-16]
leave
ret
consecutiveZeroPairs(int):
push rbp
mov rbp, rsp
sub rsp, 32
mov DWORD PTR [rbp-20], edi
cmp DWORD PTR [rbp-20], 1
jne .L4
mov eax, 0
jmp .L5
.L4:
cmp DWORD PTR [rbp-20], 2
je .L6
cmp DWORD PTR [rbp-20], 3
jne .L7
.L6:
mov eax, 1
jmp .L5
.L7:
mov eax, DWORD PTR [rbp-20]
mov esi, eax
mov edi, 2
call __gnu_cxx::__promote_2<int, int, __gnu_cxx::__promote<int, std::__is_integer<int>::__value>::__type, __gnu_cxx::__promote<int, std::__is_integer<int>::__value>::__type>::__type std::pow<int, int>(int, int)
movapd xmm1, xmm0
movsd xmm0, QWORD PTR .LC0[rip]
divsd xmm1, xmm0
movapd xmm0, xmm1
cvttsd2si eax, xmm0
mov DWORD PTR [rbp-4], eax
mov eax, DWORD PTR [rbp-4]
add eax, eax
add eax, 1
.L5:
leave
ret
main:
push rbp
mov rbp, rsp
sub rsp, 16
mov DWORD PTR [rbp-4], 5
mov eax, DWORD PTR [rbp-4]
mov edi, eax
call consecutiveZeroPairs(int)
mov esi, eax
mov edi, OFFSET FLAT:std::cout
call std::basic_ostream<char, std::char_traits<char> >::operator<<(int)
mov esi, OFFSET FLAT:std::basic_ostream<char, std::char_traits<char> >& std::endl<char, std::char_traits<char> >(std::basic_ostream<char, std::char_traits<char> >&)
mov rdi, rax
call std::basic_ostream<char, std::char_traits<char> >::operator<<(std::basic_ostream<char, std::char_traits<char> >& (*)(std::basic_ostream<char, std::char_traits<char> >&))
mov eax, 0
leave
ret
__static_initialization_and_destruction_0(int, int):
push rbp
mov rbp, rsp
sub rsp, 16
mov DWORD PTR [rbp-4], edi
mov DWORD PTR [rbp-8], esi
cmp DWORD PTR [rbp-4], 1
jne .L12
cmp DWORD PTR [rbp-8], 65535
jne .L12
mov edi, OFFSET FLAT:std::__ioinit
call std::ios_base::Init::Init()
mov edx, OFFSET FLAT:__dso_handle
mov esi, OFFSET FLAT:std::__ioinit
mov edi, OFFSET FLAT:std::ios_base::Init::~Init()
call __cxa_atexit
.L12:
nop
leave
ret
_GLOBAL__sub_I__Z20consecutiveZeroPairsi:
push rbp
mov rbp, rsp
mov esi, 65535
mov edi, 1
call __static_initialization_and_destruction_0(int, int)
pop rbp
ret
.LC0:
.long 0
.long 1076363264
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