C++ How can I make the my code continue if the user types in Y for Yes and N for
ID: 3807710 • Letter: C
Question
C++
How can I make the my code continue if the user types in Y for Yes and N for no?
#include<iostream>
#include<cmath>
#include <conio.h>
#include "BubbleSort.h"
using namespace std;
int main ();
char ans;
bool IsInteger(float num){
//Floor function gives the largest integer value present in the number
//Floor is from cmath library
//floor(num)!=num if num is not integer
return std::floor(num) == num;
}
void BubbleSort(int arr[], int n){
int i,temp;
bool IsSorted;
do{
IsSorted = true;
n--;
for(i = 0; i < n; i++)
//Checking for ascending order
if(arr[i] > arr[i + 1]){
temp = arr[i];
arr[i] = arr[i + 1];
arr[i + 1] = temp;
IsSorted = false;
}
else;
}while(!IsSorted);
}
int main(){
int n = 25,i;
float num;
while(n > 20){
cout<<" Please Enter in how many numbers you wish to use: ";
cin>>n;
}
int arr[n];
//Reading integers
i = 0;
while(i < n){
cout<<" Please enter in integer" <<i<<endl;
//Using float variable because if user inputs floating point, C++ will not accept with integer variables
cin>>num;
//Checking for integer
if(!IsInteger((float)num))
{
cout<<" Sorry, not an integer. Enter again. ";
continue;
}
//Checking for whole number
else if(num < 0)
{
cout<<" Sorry, not a whole number. Enter again. ";
continue;
}
arr[i] = num;
i++;
}
//Displaying the array in actual order
cout<<" The integers you entered are in the order: ";
for(i = 0; i < n; i++)
cout<<arr[i]<<endl;
//Calling method for sorting
BubbleSort(arr, n);
//Displaying the sorted array
cout<<" The integers you entered in ascending order: ";
for(i = 0; i < n; i++)
cout<<arr[i]<<endl;
cout <<" Do you wish to continue? Y/y N/n ";
cin >> ans;
cout << " Would you like to continue? Type in (Y/y) for yes and (N/n) for no ";
return 0;
}
Explanation / Answer
Hi
I have modified the code and highlighted the code change below.
#include<iostream>
#include<cmath>
//#include <conio.h>
//#include "BubbleSort.h"
using namespace std;
int main ();
bool IsInteger(float num){
//Floor function gives the largest integer value present in the number
//Floor is from cmath library
//floor(num)!=num if num is not integer
return std::floor(num) == num;
}
void BubbleSort(int arr[], int n){
int i,temp;
bool IsSorted;
do{
IsSorted = true;
n--;
for(i = 0; i < n; i++)
//Checking for ascending order
if(arr[i] > arr[i + 1]){
temp = arr[i];
arr[i] = arr[i + 1];
arr[i + 1] = temp;
IsSorted = false;
}
else;
}while(!IsSorted);
}
int main(){
int n = 25,i;
float num;
char ans='y';
while(ans=='y' || ans=='Y') {
n=25;
while(n > 20){
cout<<" Please Enter in how many numbers you wish to use: ";
cin>>n;
}
int arr[n];
//Reading integers
i = 0;
while(i < n){
cout<<" Please enter in integer" <<i<<endl;
//Using float variable because if user inputs floating point, C++ will not accept with integer variables
cin>>num;
//Checking for integer
if(!IsInteger((float)num))
{
cout<<" Sorry, not an integer. Enter again. ";
continue;
}
//Checking for whole number
else if(num < 0)
{
cout<<" Sorry, not a whole number. Enter again. ";
continue;
}
arr[i] = num;
i++;
}
//Displaying the array in actual order
cout<<" The integers you entered are in the order: ";
for(i = 0; i < n; i++)
cout<<arr[i]<<endl;
//Calling method for sorting
BubbleSort(arr, n);
//Displaying the sorted array
cout<<" The integers you entered in ascending order: ";
for(i = 0; i < n; i++)
cout<<arr[i]<<endl;
cout << " Would you like to continue? Type in (Y/y) for yes and (N/n) for no ";
cin >> ans;
}
return 0;
}
Output:
sh-4.2$ g++ -std=c++11 -o main *.cpp
sh-4.2$ main
Please Enter in how many numbers you wish to use:
2
Please enter in integer0
1
Please enter in integer1
2
The integers you entered are in the order:
1
2
The integers you entered in ascending order:
1
2
Would you like to continue? Type in (Y/y) for yes and (N/n) for no y
Please Enter in how many numbers you wish to use:
1
Please enter in integer0
4
The integers you entered are in the order:
4
The integers you entered in ascending order:
4
Would you like to continue? Type in (Y/y) for yes and (N/n) for no n
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