(PROGRAMMING IN C) Write a program which can accept binary numbers and certain o

Question

(PROGRAMMING IN C)

Write a program which can accept binary numbers and certain operations to calculate the results of those operations. The user should see something like:

Enter a 16 bit unsigned binary number:

Enter operator (+, -, *, %, /, <<, >>, |, &, ^, E)

Enter a 16 bit unsigned binary number:

The answer is: (note: the answer should be displayed in both binary and decimal)

Enter operator (+, -, *, %, /, <<, >>, |, &, ^, E)

Enter a 16 bit unsigned binary number:

The answer is: (note: this should perform the operation on the previous answer and the newly entered number)

The program should continue in this manner, until E is entered as the operator. When E is entered, the program should terminate. Hints: partition up the problem.

Create subroutines to:

• Accept input from the user and verify that they have entered a 16 bit binary number (note: you’ll need to handle binary numbers as strings) • Convert a string holding a binary number to an unsigned integer

• Convert an unsigned integer to a string holding a binary representation of that number

• Accept two numbers and an operator, perform the noted operation (hint: only capture the first < from << or > from >>, doing so will allow you to handle the operator as a simple character) Hint #2: use fgets and sscanf to take user input. scanf alone will be tough to get correct.

Explanation / Answer

#include // Needed to use IO functions using namespace std; int main() { int sumOdd = 0; // For accumulating odd numbers, init to 0 int sumEven = 0; // For accumulating even numbers, init to 0 int upperbound; // Sum from 1 to this upperbound int absDiff; // The absolute difference between the two sums // Prompt user for an upperbound cout > upperbound; // Use a while-loop to repeatedly add 1, 2, 3,..., to the upperbound int number = 1; while (number sumEven) { absDiff = sumOdd - sumEven; } else { absDiff = sumEven - sumOdd; } // Print the results cout

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