C programming C programming C programming Midterm (graded out of 100 points) Pro

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C programming C programming
C programming
Midterm (graded out of 100 points) Problem 1: Write a program which can accept binary numbers and certain operations to calculate the results of those operations. The user should see something like: Enter a 16 bit unsigned binary number Enter operator x, k, I, &, A, E) Enter a 16 bit unsigned binary number The answer is: (note: the answer should be displayed in both binary and decimal) Enter operator x, I, &, n, E) Enter a 16 bit unsigned binary number: The answer is: (note: this should perform the operation on the previous answer and the newly entered number) The program should continue in this manner, until E is entered as the operator. When Eisentered, the program should terminate. Hints: partition up the problem. Create subroutines to: Accept input from the user and verify that they have entered a 16 bit binary number (note: you'll need to handle binary numbers as strings) Convert a string holding a binary number to an unsigned integer Convert an unsigned integer to a string holding a binary representation of that number Accept two numbers and an operator, perform the noted operation (hint: only capture the first

Explanation / Answer

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int bin_verify(char []);
int convertBinToDec(char []);
long decimalToBinary(int);

int main()
{
    char bin1[33], bin2[33], result[33];
   char ch;
   float divResult;
    int len1, len2, check,dec1,dec2,decResult;
   long binResult;


   //printf("Entered unsigned binary and their decimal numbers %s = %d and %s = %d: ",bin1,dec1,bin2,dec2);
   printf("Enter binary numbers 1 : ");
        scanf("%s", bin1);
       printf("Enter binary numbers 2 : ");
        scanf("%s", bin2);
        check = bin_verify(bin1);
   if (check==1)
    {
        printf("Invalid binary number %s. ", bin1);
        exit(0);
    }
    check = bin_verify(bin2);

    if (check==1)
    {
        printf("Invalid binary number %s. ", bin2);
        exit(0);
    }
    dec1 = convertBinToDec(bin1);
   dec2 = convertBinToDec(bin2);
  
   while(1)
   {
  
       printf("Enter the operation from the operator(+, -, /, *, %,E) ");
       scanf("%c", &ch);
  
       switch(ch)
       {
            case '+':
                    decResult = (dec1+dec2);
                   binResult = decimalToBinary(decResult);
                   printf("%s + %s = %d (%l) ", bin1, bin2,decResult,binResult);
                    break;  
            case '-': decResult = dec1 - dec2;
                      binResult = decimalToBinary(decResult);
                     printf("%s - %s = %d (%l) ", bin1, bin2,decResult,binResult);
                     break;
            case '*': decResult = dec1 * dec2;
                      binResult = decimalToBinary(decResult);
                     printf("%s * %s = %d (%l) ", bin1, bin2,decResult,binResult);
                     break;
           case '/': divResult = dec1 / dec2;
                     binResult = decimalToBinary(decResult);
                     printf("%s / %s = %f (%l) ", bin1, bin2,divResult,binResult);
                     break;
           case '%': decResult = dec1 % dec2;
                     binResult = decimalToBinary(decResult);
                     printf("%s % %s = %d (%l) ", bin1, bin2,decResult,binResult);
                     break;
           case 'E':
                     exit(0);
                     break;     
       }
  
   }
   
    return 0;
}

long decimalToBinary(int n)
{
    int remain;
    long bin = 0, i = 1;

    while(n != 0)
   {
        remain = n%2;
        n = n/2;
        bin= bin + (remain*i);
        i = i*10;
    }
    return bin;
}

int convertBinToDec(char str[])
{  
int sum = 0,s= strlen(str)-1;
   for(int j=0; s >= 0; s--, ++j)
   {
       if(str[s] == '1')
       {
        sum = sum + pow(2,j);
       }
     }
return sum;
}

int bin_verify(char str[])
{
    int i,len;
   len = strlen(str);
//printf("String Length:%d ",strlen(str));
if(len != 16)
   return 1;
else
{
   for (i = 0; i < len; i++)
    {
        if ((str[i] - '0' != 1 ) && (str[i] - '0' != 0))
        {
            return 1;
        }
    }
}
    return 0;
}

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