automata theory Consider the following alphabet: Sigma = {[0 0], [0 1], [1 0], [
ID: 3809651 • Letter: A
Question
automata theory
Consider the following alphabet: Sigma = {[0 0], [0 1], [1 0], [1 1]} Here, Sigma contains all rows of 0s and 1s of size 2, A string of symbols in Sigma gives two columns of 0 and 1's. Consider each column to be a binary number and let: L = {w Element Sigma* | the last column of w is twice the first column} For example [0 0] [0 1] [1 0] [0 0] Element L (because the first columns form the number 0010 =2 and the second columns form the binary number 0100 = 4) and [0 0] [0 1] [1 0] [0 1] NotElement L (because the first columns form 0010 = 2 and the second columns form 0101 = 5). Show that L is regular.Explanation / Answer
with the given size of row is 2, no of possible column= 1,2,4,8
that will be written as [00][01], [00][10],[01][00],[10][00],
so the no of column is finite.
finite language is always regular.
so that given L is regular.
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