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Shifting and Instructions Part I. Create an eight-bit word and then perform thre

ID: 3810759 • Letter: S

Question

Shifting and Instructions

Part I. Create an eight-bit word and then perform three of the shifting operations on it.

(For ease of reading, I suggest that the word be broken into two 4-bit pieces separated by a blank space (i.e. xxxx xxxx)

The possible shifting operations include:

Logical Shift Right

Logical Shift Left

Rotate Right

Rotate Left

Arithmetic Shift Right

Arithmetic Shift Left

Each operation should be performed independently on the original 8-bit word.

Part II

Evaluate a short algebraic expression using code with three-operand instructions. The expression should have a minimum of three operands and 2 operators. Operands may be alpha or numeric.

You may only use registers A through F, plus X and T.

Registers A through F may not be changed, i.e. their values are fixed.

Register T may be used as a temporary register, and Register X must contain the final answer.

Show the postfix for the expression, and then use a stack to evaluate the expression.

As an example, consider X=A +B + C * D

The three-operand instructions would be:

   ADD X, A, B

   MUL T, C, D

   ADD X, X, T

The Postfix would be AB+CD*+

The stack would be:

        PUSH    / A onto the stack

        PUSH    / B onto the stack

        ADD      /pop A & B, add them, and push the answer back on the stack

        PUSH    /C

        PUSH   / D

        MUL   /pop C & D, multiply them, and push the answer back on the stack

        ADD    / pop X & T, add them, and push the answer back on the stack

         POP    / X off the stack

It is important to note that operational hierarchy dictates that

we first perform all arithmetic inside inner parentheses;

then inside outer parentheses;

then do multiplication and division operations before addition and subtraction operations.

Explanation / Answer

PUSH A TO STACK

PUSH +TO POSTFIX EXPRESSION

PUSH B TO STACK

PUSH +TO POSTFIX EXPRESSION .HERE IN THIS PROBLEM OPERATOR IS SAME.SO ONE +CAN BE

REMOVED AND INSERTED INTO STACK.

PUSH C TO STACK

PUSH * TO POSTFIX

PUSH D TO STACK

TAKE THE HIGHER PRECEDENCE * AND ADD TO POSTFIX

LEFT OVER + COMES TO POSTFIX

FINAL ANSWER IS AB+CD*+

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