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Java programming ( JavaFX ) =========== thank you for helping ============= Crea

ID: 3812953 • Letter: J

Question

Java programming (JavaFX )

=========== thank you for helping =============

Create a JavaFX program that helps the user keep track of their passwords.

There must be a screen to login - with a username(ID) and a password

If the user doesn’t have a username and password, there must be a screen to create a new one.

Passwords must be between 8 and 10 alphanumeric characters, have at least 1 capital letter, 1 number, and one special character NOT a space

Usernames must be checked against existing usernames - if a username that already exists is chosen on registration, you must give an appropriate error message and allow the user to pick a new user name

This project should have:

An Abstract Password class with a print mechanism for passwords and an interface for validating passwords

A simple password class that allows for unvalidated passwords

A complex password class that has a validation method that throws an exception

-------------------------------------------------------------------------------------

Here is the UML for abstract class I made!!

I want this abstract class should seperate into simple class and complex class to keep track of their username and password.

<UserName>

+UserName()

+UserName (string password)

+UserName (password other)

+getUserName: string

+setUserName (string password ):void

+checkmatch (string input):boolean

<password>

+password()

+password (string password)

+password (password other)

+getpassword: string

+setpassword (string password ):void

+checkmatch (string input):boolean

Explanation / Answer

import java.util.Scanner;

/** category GraphColoring **/
public category GraphColoring
non-public int V, numOfColors;
personal int[] color;
personal int[][] graph;

/** operate to assign color **/
public void graphColor(int[][] g, int noc)
answer found **/
if (v == V)
throw new Exception("Solution found");
/** strive all colors **/
for (int c = 1; c &lt;= numOfColors; c++)
  
}
}
/** operate to see if it's valid to allot that color to vertex **/
public Boolean isPossible(int v, int c)
one &amp;&amp; c == color[i])
come false;
come true;
}
/** show resolution **/
public void display()
  

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