Please use C programming not C++ The factorial of a non-negative integer n is wr

Question

Please use C programming not C++

The factorial of a non-negative integer n is written n! (pronounced "n factorial") and is defined as follows: n!= n x (n - 1) x (n - 2) x...x (for values of n greater than or equal to 1) and n! = 1 (for n = 0). For example, 5! = 5 times 4 times 3 times 2 times 1, which is 120. Write a program that reads a non-negative integer and computes and prints its factorial if the number input is smaller than 5 computes and prints the square of the factorial value for the input number if the input number is larger or equal to 5. For example, if you input 6. the output should be 720*720 = 51, 840. Show the result for both cases.

Explanation / Answer

#include <stdio.h>

int factorial(int n)
{
if(n==0 || n==1)
return 1;
else
{
return (n*factorial(n-1));
}
}

int main() {
  
int n;
scanf("%d", &n);
int result = factorial(n);
if(n < 5)
printf("%d", result);
else if(n >= 5)
printf("%d",(result * result));
  
return 0;
}

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