A design engineer wants to construct a sample mean chart for controlling the ser
ID: 381527 • Letter: A
Question
A design engineer wants to construct a sample mean chart for controlling the service life of a halogen headlamp his company produces. He knows from numerous previous samples that this service life is normally distributed with a mean of 500 hours and a standard deviation of 20 hours.
On three recent production batches, he tested service life on random samples of four headlamps with these results:
What is the sample mean service life for sample 2? (Keep two decimal places)
Your Answer:
Sample Hours 1 499 504 489 508 2 511 506 498 476 3 496 500 503 505Explanation / Answer
Considering the given question and the details of hours of service life for Sample-2 are as follows,
Mean can be defined as the average of all the entities considered for calculation
Hence in this case,
Mean = (Sum of total of all hours for sample-2) / Count of number of individual entities considered
Therefore,
Mean = (x1 + x2 + x3 + x4) / 4
(Since total no of entries in sample-2 is only 4)
Mean = (511+506+498+476) / 4
= 1991 / 4
Mean = 497.75
Hence for Sample-2, Mean is 497.75.
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