Given a link with a maximum transmission rate of 84.3 Mbps. Only two computers,

Question

Given a link with a maximum transmission rate of 84.3 Mbps. Only two computers, X and Y, wish to transmit starting at time t = 0 seconds. Computer X sends fileX (3 MiB) and computer Y sends fileY (60 KiB), both starting at time t = 0. Computer X gets the transmission medium first, so Computer Y must wait. For the following calculations, assume maximum transmission rate during transmission. Suppose that entire files are sent as a stream (no packets, no multiplexing). At what time (t = ?) would FileX finish transmitting? Give answer in seconds, without units, and round to two decimal places (e.g. for an answer of 12.4567 seconds you would enter "12.46" without the quotes)

Explanation / Answer

Since transmission rate is 84.3 Mbps and fileX is of the 3MiB.

first we need to convert the file size from mega byte to mega bits.

3MiB = 3*8Mb = 24Mb.

Time required to transmit the file as a stream = 24/84.3= 0.28469s~= 0.28S

t=0.28s

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