What is the output of the loop? Dim k As Integer For k = 1 To 5 Step 2 IblOut.Te

Question

What is the output of the loop? Dim k As Integer For k = 1 To 5 Step 2 IblOut.Text = IblOut.Text & k & " " Next a. 1 2 3 b. 1 3 5 c. 1 3 5 7 d. 1 2 3 4 5 In the code word "Microsoft" appears ________ times and word "VB" appears ______ times. Dim j As Integer Dim k As Integer For j = 1 To 7 For k = 1 To 2 1stOut.Items.Add ("VB") Next 1stOut.Items.Add ("Microsoft") Next a. 7 2 b. 7 9 e. 7 14 d. 14 7 The loop needs to display odd integers from 1 to 50. Fill in the missing loop test. a. num = 1 To 50 b. num = 50 To 1 Step -1 c. num = 0 To 50 Step 2 d. num = 1 To 49 Step 2 What is the output of the code? Assume j and k have been declared as integers. For j = 1 To 3 For k = 1 To 2 IblOut.Text = IblOut.Text & " * " Next IblOut.Text = IblOut.Text & vbCRLF Next a. ****** b. ****** c. ** ** ** d. *** **** c. * ** ***

Explanation / Answer

6.

Step 2 means increment by 2

So, k would have values -

k = 1 for 1st interation

k = 1+2 = 3 for 2nd iteration

k = 3+2 = 5 for 3rd iteration

The output would be just k values with space in between

OUTPUT would be:

1 3 5

The answer is option 'b'.

7.

For each iteration of j, k would iterate twice i.e., for k =1 and k =2

So, VB would be printed twice for every iteration of j and "Microsoft" would be printed once.

j has values from 1 to 7.

So, VB would print 7*2 = 14 times whereas "Microsoft" would print 7 times.

Hence, the answer is option 'c'.

j = 1:

   k = 1: prints "VB"
  
   k = 2: prints "VB"
  
   prints "Microsoft"
  
j = 2:

   k = 1: prints "VB"
  
   k = 2: prints "VB"
  
   prints "Microsoft"
  
This continues for all j =1 to j = 7.

8.

Step 2 means increment by 2

So, to print odd numbers from 1 to 50, we need to run loop from 1 to 49 by incrementing 2 for every iteration.

num = 1 To 49 Step 2 will give -

1st iteration: num = 1

2nd iteration: num = 1+2 = 3

3rd iteration: num = 3+2 = 5

and so on..

So, the answer is option 'd'.

9.

For each iteration of j, k has 2 iterations for k = 1 and k = 2

j = 1:

   k = 1: prints "*"
  
   k = 2: prints "*"
  
   vbCRLF indicates new line
  
j = 2:

   k = 1: prints "*"
  
   k = 2: prints "*"
  
   vbCRLF indicates new line
  
j = 3:

   k = 1: prints "*"
  
   k = 2: prints "*"
  
   vbCRLF indicates new line
  
So, the OUTPUT would be -

**
**
**

So, the answer is option 'c'.

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