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Activity10 Expected Time Variance 12 16 6 2 2 10 12 4 3a) From the table above c

ID: 382155 • Letter: A

Question

Activity10 Expected Time Variance 12 16 6 2 2 10 12 4 3a) From the table above calculate the expected time for each of the activities(A to J)(4 Marks). 3b)) From the table above calculate the variance for each of the activities(A Uo J)(4 Marks).(Hint: te = a +46n) + b, 2-Pea)12 ) Question 2 A) Lucy's Pancake House, a no-frills diner along a major interstate, has discovered that if precious employee time is not wasted on frivolous duties such as cleaning work surfaces, properly storing ingredients, and pest control, they can achieve an average output rate of 25 customers per hour. If the diner was designed to accommodate a maximum of 30 customers per hour, what is the utilization? (4Marks) B) The seven-person maintenance function at a hospital performs both preventive and corrective maintenance on hundreds of items each month. All the workers are scheduled for 40 hours per week and there are four weeks in a month. It is the goal of the maintenance department to achieve 90% utilization with a mix of two-thirds preventive maintenance and one-third corrective maintenance. How many hours each month are spent performing preventive maintenance if they achieve their 90% utilization and correct/preventive mix targets? (4Marks)

Explanation / Answer

Answer to Q.1 :

Expected time of each activity = ( b – a) /6

Variance of each activity = ( b – a)^2/36

Accordingly the filled up table as follows :

ACTIVITY

a

m

b

Expected duration

Variance = ( b - a)^2/36

A

4

7

10

7

1.00

B

2

8

20

9

9.00

C

8

12

16

12

1.78

D

1

2

3

2

0.11

E

6

8

22

10

7.11

F

2

3

4

3

0.11

G

2

2

2

2

0.00

H

6

8

10

8

0.44

I

4

8

12

8

1.78

J

1

2

3

2

0.11

Answer to Q.2

= 7 persons x 40 hours / week x 4 weeks/ month = 1120 hours

Total utilization of 7 members team = 90% of 1120 hours = 1008 hours

Thus, time spent on preventive maintenance

= 2/3 rd of 1008 hours

= 672 hours

NUMBER OF HOURS EACH MONTH SPENT ON PREVENTIVE MAINTENANCE = 672 HOURS

ACTIVITY

a

m

b

Expected duration

Variance = ( b - a)^2/36

A

4

7

10

7

1.00

B

2

8

20

9

9.00

C

8

12

16

12

1.78

D

1

2

3

2

0.11

E

6

8

22

10

7.11

F

2

3

4

3

0.11

G

2

2

2

2

0.00

H

6

8

10

8

0.44

I

4

8

12

8

1.78

J

1

2

3

2

0.11

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