public class CallStack{ // Called by func1() void func2 (){ System.out.println(\
ID: 3822975 • Letter: P
Question
public class CallStack{
// Called by func1()
void func2 (){
System.out.println("In func2 method");
int a = 0;
int b;
b = 10 / a;
}
//Called by Main
void func1(){
System.out.println("In func1 method");
this.func2 ();
System.out.println("Back in func1 method");
}
public static void main (String args[]){
CallStack myCallStack;
myCallStack = new CallStack();
System.out.println("In the main method");
myCallStack.func1 ();
}
}
Explanation / Answer
package org.students;
public class CallStack {
// Called by func1()
void func2 (){
System.out.println("In func2 method");
int a = 0;
int b;
if(a==0)
//Here we are creating exception and throwing out of the func2() function
throw new IllegalArgumentException("Invalid.Divided by zero");
else
b = 10 / a;
}
//Called by Main
void func1(){
System.out.println("In func1 method");
try {
this.func2 ();
} catch (Exception e) {
System.out.println(e);
}
System.out.println("Back in func1 method");
}
public static void main (String args[]){
CallStack myCallStack;
myCallStack = new CallStack();
System.out.println("In the main method");
myCallStack.func1 ();
}
}
__________________
Output:
In the main method
In func1 method
In func2 method
java.lang.IllegalArgumentException: Invalid.Divided by zero
Back in func1 method
______________Thank You
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